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Sergio039 [100]
3 years ago
5

Which of the following work mostly severaly affect a human population

Chemistry
1 answer:
Arada [10]3 years ago
6 0
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Generally, observed behavior that can be formulated into a statement, sometimes mathematical in nature, is called a(n):
earnstyle [38]

Answer:

Generally, observed behavior that can be formulated into a statement, sometimes mathematical in nature, is called a natural law- D.

7 0
3 years ago
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Sum of brother and sisters age is 26. Four times the brothers age is subtracted from three times the sisters age, the difference
lana66690 [7]

Answer : The ages of the brother and sister are, 10 and 16 years respectively.

Solution :

Let the age of brother be 'x' and the age of sister be 'y'

There are two equations formed which are,

x + y = 26      ..........(1)

3y - 4x = 8     ..........(2)

First we have to multiple equation (1) by 4 and then added equation (1) and (2), we get the value of 'y'.

4x+4y+3y-4x=8+26\\\\7y=112\\\\y=16

Now put the value of 'y' in equation (2), we get the value of 'x'

3(16) - 4x = 8

4x = 40

x = 10

The age of brother = x = 10 years

The age of sister = y = 16 years

Therefore, the ages of the brother and sister are, 10 and 16 years respectively.

3 0
3 years ago
Which formula represents a saturated hydrocarbon
GenaCL600 [577]
Saturated hydrocarbons are organic compounds that contain only single bonds between the carbon atoms. They are known to be the simplest organic compounds. They are termed as such because they are saturated with water. Examples are the alkanes (ethane, methane, propane, butane, etc.).
6 0
3 years ago
Which of these prevents conduction from occuring?
valentinak56 [21]
C. Equal temperatures
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3 years ago
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Calculate the pH of a solution prepared by dissolving 0.150 mol of benzoic acid and 0.300 mol of sodium benzoate in water suffic
jok3333 [9.3K]

Answer : The pH of a solution is, 4.50

Explanation : Given,

K_a=6.30\times 10^{-5}

Concentration of benzoic acid (Acid) = 0.150 M

Concentration of sodium benzoate (salt) = 0.300 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.30\times 10^{-5})

pK_a=5-\log (6.30)

pK_a=4.20

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=4.20+\log (\frac{0.300}{0.150})

pH=4.50

Thus, the pH of a solution is, 4.50

8 0
3 years ago
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