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noname [10]
3 years ago
6

Will give brainliest

Chemistry
2 answers:
docker41 [41]3 years ago
8 0
62.12 is the answer I think
Furkat [3]3 years ago
6 0
For the empirical formula question: C3H8O2
Work:

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an open box of bandages is on the floor. bandage wrappers are found nearby. What is the chemical treatment?
katrin2010 [14]
By what I have learned I don't think that is chemical but if I had to guess I would say the chemical treatment is they are exposed to air
3 0
4 years ago
Read 2 more answers
While investigating greenhouse gases, I measured 0.1875 grams of carbon dioxide in a 500-gram sample of the atmosphere. What is
Harlamova29_29 [7]

Answer:

[CO₂] = 375 ppm

Explanation:

We can determine the concentration in value of ppm

ppm = mass of solute (mg) / mass of solution (kg)

Solution: atmosphere

Solute: CO₂

We convert the mass of CO₂ from g to mg → 0.1875 g . 1000 mg / 1g = 187.5 mg

We convert the mass of the atmosphere from g to kg: 500 g . 1 kg/1000g = 0.500 kg

ppm = 187.5 mg / 0.500kg = 375

6 0
3 years ago
Three isotopes of oxygen are oxygen-16 oxygen-17 and oxygen-18. true or false?
Ivanshal [37]

Answer:

Oxygen is composed of three isotopes: oxygen-16, oxygen-17 and oxygen-18 and has an average atomic mass of 15.9980 amu. Oxygen-17 has a mass of 16.992 amu and makes up 0.035% of oxygen. Oxygen-16 has a mass of 15.982 amu and Oxygen-18 has a mass of 17.984 amu.

4 0
2 years ago
Convert the following<br> 4. 100 cm =<br> 5. 453 m = _<br> 6. 89847nm = _<br> 7. 3Mm =
fredd [130]
4. I meter
5. 0.453 kilometers
6. 89.84700 microns
7. Yo momma
6 0
3 years ago
Calculate the theoretical percentage of water for the following hydrates.
Svetradugi [14.3K]

Answer:

(a) \% H_2O=10.65\%

(b) \% H_2O=32.2

Explanation:

Hello.

For this questions we must consider the ratio of the molar mass of water to  hydrated compound molar mass as shown below:

(a) In this case, we can consider that inside the manganese (II) sulfate monohydrate, whose molar mass is 169.02 g/mol, there is one water molecule that has a molar mass of 18 g/mol, for which the theoretical percentage of water is:

\% H_2O=\frac{18g/mol}{169.0g/mol} *100\%\\\\\% H_2O=10.65\%

(b) In this case, we can consider that inside the manganese (II) sulfate tetrahydrate, whose molar mass is 223.1 g/mol, there are four water molecules that have a molar mass of 4*18 g/mol, for which the theoretical percentage of water is:

\% H_2O=\frac{4*18g/mol}{223.1g/mol} *100\%\\\\\% H_2O=32.27\%

Best regards.

8 0
3 years ago
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