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DanielleElmas [232]
3 years ago
9

Which is an example of an exothermic process?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

I think it's E. heating of water

Because exothermic process discharges heat, causing the temperature of the prompt environment to rise

Please correct me if I'm wrong!! I'd be happy to fix it!! :)

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What happens in this circuit if one of the light bulbs burns out?
bulgar [2K]
4.The other light bulb will stay on and glow brightly.
4 0
2 years ago
How many solutions are there in the following equation.
givi [52]
When they ask you for the solution they are usually asking for x. So solve for X.
X=-12  so you only have one solution. so the answer is B
6 0
3 years ago
Is ammonium ion a bronsted base
Leokris [45]

Unlikely. It's unlikely for ammonium ion {\text{NH}_4}^{+} to accept a proton \text{H}^{+} and act as a Bronsted-Lowry Acid.

<h3>Explanation</h3>

What's the definition of Bronsted-Lowry acids and bases?

  • Bronsted-Lowry Acid: a species that can donate one or more protons \text{H}^{+} in a reaction.
  • Bronsted-Lowry Base: a species that can accept one or more protons \text{H}^{+}

Ammonium ions {\text{NH}_4}^{+} are positive. Protons \text{H}^{+} are also positive.

Positive charges repel each other, which means that it will be difficult for {\text{NH}_4}^{+} to accept any additional protons. As a result, it's unlikely that {\text{NH}_4}^{+} will accept <em>any</em> proton and act like a Bronsted-Lowry Base.

6 0
3 years ago
Below is a picture of two blocks made of different materials. Block A Block B grams grams If Block A is located on the Moon and
AURORKA [14]

Answer:

A

Explanation:

this is because density is the mass per unit volume of an object

4 0
2 years ago
Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce
levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

[Ag^{+}] = 0.0390 M

When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

        1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]

       [SO^{2-}_{4}] = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

         CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}

      K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788

           [Ca^{2+}] = 0.00625 M

Now, we will calculate the percentage of Ca^{2+} remaining in the solution as follows.

               \frac{0.00625}{0.05} \times 100

                 = 12.5%

And, the percentage of Ca^{2+} that can be separated is as follows.

                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

4 0
3 years ago
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