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posledela
3 years ago
9

which of the following are needed to determine how long an object is in projectile motion? tell me all that apply. a. the initia

l velocity of the object b. the mass of the object c. the horizontal distance the object travels as it falls d. the vertical distance the object travels as it falls
Physics
1 answer:
sertanlavr [38]3 years ago
4 0
Distance that the object falls
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Hey there,
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8 0
3 years ago
A marble rolls with a speed of 15 m/s and has a momentum of 0.15 kg*m/s. What is its mass?<br>​
prisoha [69]

Answer:

m = 0.01 kg

Explanation:

Given that,

Momentum of the marble, p = 0.15 kg-m/s

Speed of the marble, v = 15 m/s

We need to find its mass. We know that,

Momentum, p = mv

Where

m is the mass

m=\dfrac{p}{v}\\\\m=\dfrac{0.15}{15}\\\\m=0.01\ kg

So, the mass of the marble is equal to 0.01 kg.

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3 years ago
How does the mitochondria help to maintain homeostasis for the cell?
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6 0
2 years ago
A scientist measures the growth of a bamboo plant over time. The table above shows the results. What is the best interference fo
lisabon 2012 [21]

(B) 2.25cm

<u>Explanation:</u>

Given:

At 40 hours, the height of the bamboo plant is 2.1cm

At 50 hours, the height of the bamboo plant is 2.4cm

Height of the bamboo plant after 45 hours = ?

The difference in length from 40 to 50 hours = 2.4 - 2.1cm

                                                                      = 0.3 cm

Mean of 40 and 50 is 45.

Thus,

At 45 hours, the height will increase by 0.3/2

                                                         = 0.15 cm

Height at 45 hour = 2.1 + 0.15cm

                           = 2.25cm

Therefore, the height of the plant after 45 hours is 2.25cm

7 0
3 years ago
There is a refrigerator running in a room, the heat flowing into the refrigerator from the outside is 40 J/s, and the refrigerat
Mamont248 [21]

Answer:

(A) 140 j/sec (b) 1.26 K

Explanation:

We have given the heat heat flowing into the refrigerator = 40 J/sec

Work done = 40 W

(a) So the heat discharged from the refrigerator =heat\ flowing\ in\ refrigerator+work\ done=40+100=140j/sec

(b) Total heat absorbed =140 j/sec =140\times 3600=504000j/hour

Let the temperature be \Delta T

Heat absorbed per hour =504000 [tex]=400\times 10^3\times \Delta T

So  \Delta T=\frac{504000}{400000}=1.26K

8 0
2 years ago
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