The velocity of A is 5.16m/s²
<u>Explanation:</u>
Given-
mass of cylinder A, mₐ = 2kg
mass of cylinder B, mb = 10kg
Distance, s = 2m
Velocity of A, v = ?
Let acceleration due to gravity, g = 10m/s²
We know,

We know,


Therefore, the velocity of A is 5.16m/s²
Answer:
velocity of mass when it slides of will be 1.36 m/sec
So option (b) will be correct option.
Explanation:
We have given mass of the slits m = 75 gram = 0.075 kg
Radius r = 75 cm = 0.75 m
Coefficient of kinetic friction 
Acceleration due to gravity 
When the mass slides of


So velocity of mass when it slides of will be 1.36 m/sec
So option (b) will be correct option.
Explanation:
Given that,
Each vertical line on the graph is 1 millisecond (0.001 s) of time.
We need to find the period and the frequency of the sound wave. The period of a wave is equal to the each vertical line on graph i.e. 0.001 s.
Let f be the frequency of the sound wave. So,
f = 1/T
i.e.

So, the period and the frequency of the sound waves is 1 milliseond and 1000 Hz respectively.
I think it is D
Hope my answer help you?