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Effectus [21]
3 years ago
14

A student was heard saying "the mass of a ball on the moon is one sixth it's mass on earth"Give a reason why this statement is w

rong?
Physics
2 answers:
andrew11 [14]3 years ago
8 0
Masd doesn't change when something is placed on the moon it's weignt andgravitational pull from the moon dp though
Liula [17]3 years ago
5 0
Mass doesn't change when something is placed on the moon, it's weight and gravitational pull from the moon do , though.
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Suppose two waves collide, and the temporary combined wave that results is smaller than the original waves. what term best descr
BlackZzzverrR [31]
The collision of the two waves would bring force and that would make the new wave smaller
3 0
3 years ago
if a freely falling object were somehow equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s/
Pie

Answer: The speed reading would increase each second by 20m/s

Explanation:

Acceleration is the change in velocity per unit change in time.

Acceleration = velocity/time

∆v = a∆t

Given a = g = 20m/s/s (acceleration due to gravity)

∆t = 1 sec

∆v = 20m/s/s × 1s

∆v = 20m/s

Therefore, the speed reading would increase each second by 20m/s

3 0
4 years ago
Two carts, one twice as heavy as the other, are at rest on a horizontal track. A person pushes each cart for 8 s. Ignoring frict
GalinKa [24]

Answer:

The correct option is: B that is 1/2 K

Explanation:

Given:

Two carts of different masses, same force were applied for same duration of time.

Mass of the lighter cart = m

Mass of the heavier cart = 2m

We have to find the relationship between their kinetic energy:

Let the KE of cart having mass m be "K".

and KE of cart having mass m be "K1".

As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.

Numerical analysis.

⇒ KE =  \frac{mv^2}{2}

⇒ KE =  \frac{mv^2}{2}\times \frac{m}{m}

⇒ KE =  \frac{m^2v^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(mv)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2m}=\frac{(F\times t)^2}{2m}

Now,

Kinetic energies and their ratios in terms of momentum or impulse.

KE (K) of mass m.

⇒ K=\frac{(F\times t)^2}{2m}           ...equation (i)

KE (K1) of mass 2m.

⇒ K_1=\frac{(F\times t)^2}{2\times 2m}

⇒ K_1=\frac{(F\times t)^2}{4m}         ...equation (ii)

Lets divide K1 and K to find the relationship between the two carts's KE.

⇒ \frac{K_1}{K} =\frac{(F\times t)^2}{4m} \times \frac{2m}{(F\times t)^2}

⇒ \frac{K_1}{K} =\frac{2m}{4m}

⇒ \frac{K_1}{K} =\frac{2}{4}

⇒ \frac{K_1}{K} =\frac{1}{2}

⇒ K_1=\frac{K}{2}

⇒ K_1=\frac{1}{2}K

The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.

7 0
3 years ago
A 2.50 gram rectangular object has measurements of 22.0 mm, 13.5 mm, and 12.5 mm. what is the objectâs density in units of g/ml?
navik [9.2K]
<span>To calculate the density, we must first calculate the volume of the object. For a rectangle, the volume is equal to V=l*w*h. In this case, V=22*13.5*12.5=3712.5 mm^3. Next we have to convert the mm^3 to mL using the conversion factor of 1 mm^3=.001 mL. To get mL, we set up the expression 3712.5 mm^3 * (.001mL/1mm^3) = 3.7125 mL. Finally, to get the density, we know density is mass over volume, so we set the expression p=m/V=2.5g/3.7125mL=.6734 which rounded to 3 significant figures is .673. The answer will be .673</span>
8 0
3 years ago
A switch in an electric circuit controls the flow of electrons in the circuit.
Delvig [45]

Answer:

when you switch off an electrical curcuit you tend to create a 'break' in the curcuit,preventing the electric current to flow around the curcuit,this can be caused by a simple switch or 'break'

Explanation:

7 0
3 years ago
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