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fenix001 [56]
3 years ago
14

A water skier is pulled by a boat traveling with a constant velocity. Which one of the following statements is false concerning

this situation? A. The net vertical force on the skier is zero newtons. B. The net acceleration of the skier is zero m/s2. C. There is a net horizontal force on the skier in the direction the ​boat’s velocity. D. The water skier is in equilibrium. ​ E. The net force on the skier is zero newtons.
Physics
1 answer:
ycow [4]3 years ago
6 0

Answer:

C. There is a net horizontal force on the skier in the direction the ​boat’s velocity.

Explanation:

This is because, according to Newton's First law of motion, when an object which in this case is the skier tends to be in equilibrium because it travels at a constant velocity, there is no net acceleration of the skier, and this causes the net force on the skier to be equal to zero.

Therefore in this question, option C which states that "There is a net horizontal force on the skier in the direction the ​boat’s velocity" is a false statement.

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dado los vectores a=3.5 b=4 c=6.5 , si se sabe que a+b+c=0 (resultante) cual es el angulo formado por A y B?
lawyer [7]

cos(A) = (b2 + c2 − a2) / 2bc = (16+6.5^2-3.5^2)/(2*4*6.5) = 0.88461538  so A = cos−1 (0.88461538) = 27.79 Deg cos(B) = (c2 + a2 − b2)/2ca = (3.5^2+6.5^2-16)/(2*3.5*6.5) = 0.84615385  so B = cos−1 (0.84615385) = 32.2 Deg

6 0
3 years ago
Which circuit has the larger equivalent resistance: a circuit with two 10 ohm resistors connected in parallel or a circuit with
Ganezh [65]

Answer:

A circuit with two 10 ohm resistors connected in series.

Explanation:

The formula for the equivalent resistance for resistors in parallel is

\frac{1}{Rt} = \frac{1}{R1} + \frac{1}{R2}   So if R1=R2= 10  \frac{1}{Rt} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10}   Rt =\frac{10}{2} =5 ohm

The formula for the equivalent resistance for resistors in series is

Rt = R1 + R2  So Rt= 10 + 10 = 20

6 0
3 years ago
A book rest on a table which it's face having a sides 30cm by 25cm . if it exerts apressure of 200pa then determine the mass of
Simora [160]

Answer:

Approximately 1.5\; \rm kg. (Assuming that this table is level, and that the gravitational field strength is g = 9.8\; \rm N \cdot kg^{-1}.

Explanation:

Convert the dimensions of this book to standard units:

\displaystyle 30\; \rm cm = 30\; \rm cm \times \frac{1\; \rm m}{100\; \rm cm}  = 0.30\; \rm m.

\displaystyle 25\; \rm cm = 25\; \rm cm \times \frac{1\; \rm m}{100\; \rm cm}  = 0.25\; \rm m.

Calculate the surface area of this book:

0.30\; \rm m  \times 0.25\; \rm m = 0.075\; \rm m^{2}.

Pressure is the ratio between normal force and the area over which this force is applied.

\displaystyle \text{Pressure} = \frac{\text{normal Force}}{\text{contact Area}}.

Equivalently:

(\text{normal Force}) = \text{Pressure} \cdot (\text{contact Area}).

In this question, \text{Pressure} = 200\; \rm Pa = 200\; \rm N \cdot m^{-2}.

It was found that (\text{contact Area}) = 0.075\; \rm m^{2} (assuming that the entire side of this book is in contact with the table.

Hence:

\begin{aligned}& (\text{normal Force}) \\ &= \text{Pressure} \cdot (\text{contact Area}) \\ &= 200\; \rm N \cdot m^{-2} \times 0.075\; \rm m^{2} \\ &= 15\; \rm N \end{aligned}.

If that the table is level, this normal force would be equal to the weight of this book:

\text{weight} = 15\; \rm N.

Assuming that the gravitational field strength is g = 9.8\; \rm N \cdot kg^{-1}. The mass of this book would be:

\begin{aligned}\text{mass} &= \frac{\text{weight}}{g} \\ &= \frac{15\; \rm N}{9.8\; \rm N \cdot kg^{-1}}\approx 1.5\; \rm kg\end{aligned}.

4 0
2 years ago
Please use this screenshot in any way you can
miskamm [114]
Ball 1 Has uchanging motion because it continually goes up no matter what. Ball 2 has no motion. And ball 3 changing motion because it goes from not moving to moving. Hope this helps
7 0
3 years ago
What is the specific heat of the solid phase?
const2013 [10]

Answer: Generally, the specific heat capacities for solids are a few hundred J / (kg °C), and for liquids they're a few thousand J / (kg °C). For gases, the same equation applies, but there are two different specific heat values.

Explanation: Ive done this before

5 0
3 years ago
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