3 years ago

(Thanks in advance)

Physics

1 answer:

Dmitrij [34]3 years ago

5 0

I would say it B) in the same direction feel free to ask me more question

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Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitu

grin007 [14]

Answer:

Explanation:

d = vo*t + ½*g*t²

d = 3*3 + ½*10*3²

d = 9 + 45

d = 54 m

entonces el objeto tiene 54 m de desplazamiento

7 0

3 years ago

Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up

Mademuasel [1]

Answer:

V = 90.51 m/s

Explanation:

From the given information:

Initial speed (u) = 0

Distance (S) = 391 m

Acceleration (a) = 18.9 m/s²

Using the relation for the equation of motion:

v² - u² = 2as

v² - 0² = 2as

v² = 2as

$v = \sqrt{2as}$

$v = \sqrt{2*18.9*391}$

v = 121.57 m/s

After the parachute opens:

The initial velocity = 121.57 m/ss

Distance S' = 332 m

Acceleration = -9.92 m/s²

How fast is the racer can be determined by using the relation:

$V= \sqrt{v^2 + 2aS'}$

$V = \sqrt{121.57^2+ 2 (-9.92)(332)}$

V = 90.51 m/s

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3 years ago

the total positive charge is QQQ = 1.62×10−6 CC , what is the magnitude of the electric field caused by this charge at point P,

balu736 [363]

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

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3 years ago

By what percent must one increase the tension in a guitar string to change the speed of waves on the string from 301 m/s to 343

garri49 [273]

Answer:

29.8 %

Explanation:

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4 years ago

A train car with mass m1 = 515 kg is moving to the right with a speed of v1 = 7.5 m/s and collides with a second train car. The

Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

$515*7.5+m2*0=(m1+m2)*4.8$

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

$515*7.5-289.6875*6 = (515+289.6875)*V$

and we have as a result:

V = 2.64 (it is moving to the right)

6 0

3 years ago