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4 years ago

Plz answer this! I am stumped

Physics

1 answer:

Gwar [14]4 years ago

6 0

MgCl2
Mg = magnesium
Cl = chlorine

Magnesium + chlorine = magnesium chloride.

This is because compounds are always written with the METAL FIRST and the NON METAL SECOND. the non metal ends in - ide when it reacts with a metal.

So ur answer would be magnesium chloride. :)

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(10%) Problem 2: The frequency range for AM radio is 540 to 1600 kHz. The frequency range for FM radio is 88.0 to 108 MHz.

Dominik [7]

188m - 556m is the wavelength range for AM radio.

2.77 - 3.40m is the wavelength range for FM radio.

1) For AM radio

f(max) = 1600 × 10³ Hz

f(min) = 540 ×10³Hz

c = fλ

λ = c/f where,

c = speed of light

f = frequency

λ= wavelength

So,

λ(min) = 3 × $10^{8}$ / 1600 × 10³ = 188 m

λ(max) = 3 × 10⁸/540 ×10³ = 556 m

So wavelength range of AM radio is 188 m - 556m

2) For FM radio

f(max) = 108 × 10⁶ Hz

f(min) = 88 × 10⁶ Hz

λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m

λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m

So wavelength range of FM radio is 2.77m - 3.40m

Learn more about frequency here brainly.com/question/10728818

#SPJ1

3 0

2 years ago

A rock is dropped off a cliff and falls the first half of the distance to the ground in t1 seconds. If it falls the second half

Hitman42 [59]

Answer:

$t2/t1 = \sqrt{2} - 1$

Explanation:

The expression for the second law of motion is given below:

h = $ut + 0.5at^2$

For first half distance

Object is initially at rest, so its initial speed u = 0

Object falls at half the distance, so h = h/2 where t = t1

Hence, we have

$h/2 = at1^2/2 - equation 1$

For second half distance:

Similarly,

$h = a(t1 + t2)^2/2 - equation 2$ where t = t1 + t2 and u= 0

Using equation 2 by equation 1

we obtain $2 = (t1 + t2)^2/t1^2$

Hence $t2/t1 + 1 = \sqrt{2}$

Hence $t2/t1 = \sqrt{2} - 1$

5 0

3 years ago

Which of the following describes glass?

iris [78.8K]

Answer:

Explanation:

Glass doesn't move freely until it is too hot and melts.

3 0

3 years ago

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t

diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

-30 = 5V0 - 122.5

-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

this is the initial speed of the egg

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

342.25-19.6y = 0

342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

this value is how high it rises above starting point

The magnitude of velocity is = 0 at its highest point

This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.

5. Please check attachment for graph

6 0

3 years ago

Will mark the brainliest

Gennadij [26K]

Answer:

OK draw a diagram - you have the force from (b) acting sown the slope and a component of the weight. Use F=ma to get the deceleration and then use SUVAT. Post your working if this doesn't work.

friction = 900N

braking = 3100N

total = 4000N

w= mxg = 1000*9.81= 9810N

total = 9810 + 4000 = 13810N

force/mass = 13810/1000 = 13.81ms^-2

then using v^2 = u^2 + 2as, i get s as 14 but it is incorrect

Explanation:

4 0

3 years ago