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Elina [12.6K]
3 years ago
13

A 12 cm radius air duct is used to replenish the air of a room 9.2 m x 5.5 m x 4.5 m every 10 min. how fast does the air flow in

the duct?
Physics
1 answer:
mote1985 [20]3 years ago
6 0
In this problem, given the dimensionns of the room and the dimension of the pipe in which air passes through, we can determine the flow of air in the duct. The area of the duct is A = pi r2 where r is equal to 12 cm. we divide this area to time which is 10 minutes, then we get the answer.
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A laser beam of unknown wavelength passes through adiffraction grating having 5510 lines/cm after striking itperpendicularly. Ta
Ivahew [28]

Answer:

Explanation:

distance between two slit  d = \frac{1 \times 10^{-2}}{5510}

d = 18.15 x 10⁻⁷ m

Let wave length of light λ

formula for  position of  first pair of bright spot

Tanθ = λ / d , λ is wave length of light and d is distance between two slit .

Tan 15.4 = \frac{\lambda}{18.15\times10^{-7}}

λ = Tan 15.4 x 18.15 x 10⁻⁷

=5 x 10⁻⁷ m

If θ be the position of next bright spot

Tanθ = 2 λ / d

= \frac{2 \times\ 5\times\ 10^ {-7}}{18.15\times10^{-7}}

=\frac{2\times5}{18.5}

θ = 28.4 degree .

7 0
3 years ago
What is the de broglie wavelength of a 149-g baseball traveling at 95.4 mph? (1 mile = 1.609 km, h = 6.63 × 10–34 j·s)?
boyakko [2]

The solution for the problem is:

Wavelength = Planck’s constant/(mass*velocity) 

Planck’s constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s 

mass = 149g = 0.149 kg 

velocity = 95.4.mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.65m/s 

h/mv = 6.63*10^-34 kg-m^2/s^2-s/(42.65m/s*0.149kg)

wavelength = 1.04 *10^-34 m

5 0
3 years ago
What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire
Paul [167]

Answer:

\Delta P=1581357.92\ Pa

Explanation:

Given:

  • diameter of hose pipe, D=0.09\ m
  • diameter of nozzle, d=0.03\ m
  • volume flow rate, \dot{V}=40\ L.s^{-1}=0.04\ m^3.s^{-1}

<u>Now, flow velocity in hose:</u>

v_h=\frac{\dot V}{\pi.D^2\div 4}

v_h=\frac{0.04\times 4}{\pi\times 0.09^2}

v_h=6.2876\ m.s^{-1}

<u>Now, flow velocity in nozzle:</u>

v_n=\frac{\dot V}{\pi.d^2\div 4}

v_n=\frac{0.04\times 4}{\pi\times 0.03^2}

v_n=56.5884\ m.s^{-1}

We know the Bernoulli's equation:

\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2

when the two points are at same height then the eq. becomes

\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}

\Delta P=\frac{\rho(v_n^2-v_h^2)}{2}

\Delta P=\frac{1000(56.5884^2-6.2876^2)}{2}

\Delta P=1581357.92\ Pa

8 0
3 years ago
A large truck breaks down out on the road and receives a push back to town by a small compact car.
Anton [14]

Answer:

A True. It agrees with Newton's third law

3 True. The car pushes the truck and goes at constant speed

Explanation:

To examine the final answers, we must silver the solution of the problem, if we see Newton's third law, action and reaction, we see that the car pushes the truck the action, the truck must oppose this force with a force applied on the car of equal magnitude, but opposite direction

In view of the above, let's review the statements.

A True. It agrees with Newton's third law

B False. Violate Newton's third law

C False  violate Newton´s third law

D False. The force is exerted by the car not specifically by the engine

E Faults if no force is exerted the truck should stop due to friction

Second question

If the two vehicles move at the same speed, the resulting force on each of them must be zero

1 False. If the truck doesn't get nine, it can't go at cruising speed

2 False if the car is accelerating it cannot go at constant speed

3 True. The car pushes the truck and goes at constant speed

4 False. If the truck slows it should slow down

5 0
3 years ago
Microwave ovens heat food through the process of A) COnduction B) Convection C) Radiation D)Stratification
Andru [333]

Answer:

\huge\boxed{Radiation}

Explanation:

In microwave, there are waves called "microwaves" as per the name. So, The heating of food is done with the help of waves. Radiation is "the transfer of heat through waves". That is why the process of heating food in a microwave is "Radiation".

5 0
3 years ago
Read 2 more answers
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