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Naya [18.7K]
3 years ago
6

Describe the universe and its components

Physics
1 answer:
svet-max [94.6K]3 years ago
5 0

The universe is a vast expanse of space.

Some components are planets, stars and galaxies.

hope that helped.

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which of the following values can you find by calculating the slope of a graph of velocity versus time position . displacement .
statuscvo [17]
The correct answer is: acceleration.

In fact, the slope of the graph of velocity versus time corresponds to the ratio between the variation of v and the variation of t:
\frac{\Delta v}{\Delta t}
But this is exactly the definition of acceleration: a= \frac{\Delta v}{\Delta t}, so acceleration is the correct answer.
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3 years ago
A charge +q is located at the origin, while an identical charge is located on the x axis at x = +0.57 m. A third charge of +2q i
Jlenok [28]

Answer:

The third charge placed is 0.80 m.

Explanation:

Given that,

Distance = 0.57 m

First charge = q

Third charge = 2q

We need to calculate the electrostatic force on charge q₁ due to q₂

Using formula of electrostatic force

F_{21}=\dfrac{kq_{1}q_{2}}{r_{1}^2}

When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is

F_{net}=F_{21}+F_{31}

The net electrostatic force on the charge at the origin doubles.

2F_{21}=F_{21}+F_{31}

F_{31}=F_{21}

\dfrac{kq_{3}q_{1}}{r_{2}^2}=\dfrac{kq_{2}q_{1}}{r_{1}^2}

\dfrac{q_{3}}{r_{2}^2}=\dfrac{q_{2}}{r_{1}^2}

r_{2}^2=\dfrac{q_{3}}{q_{2}\timesr_{1}^2}

r_{2}=\sqrt{\dfrac{q_{3}}{q_{2}}}r_{1}

Put the value into the formula

r_{2}=\sqrt{\dfrac{2q}{q}}\times0.57

r_{2}=\sqrt{2}\times0.57

r_{2}=0.80\ m

Hence, The third charge placed is 0.80 m from origin in x-axis.

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