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3 years ago

Describe the universe and its components

Physics

1 answer:

svet-max [94.6K]3 years ago

5 0

The universe is a vast expanse of space.

Some components are planets, stars and galaxies.

hope that helped.

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A 50-V de voltage source was connected in series with a resistor and capacitor. Calculate the current in A to two significant fi

Naddik [55]

Answer:

Current through circuit will be $0.2706\times 10^6A$

Explanation:

We have given source voltage v = 50 volt

Resistance $R=25Mohm=25\times 10^6ohm$

Capacitance $C=0.1\mu F=0.1\times 10^{-6}F$

Time t = 5 sec

Time constant of RC circuit is given by $\tau =RC=25\times 10^6\times 0.1\times 10^{-6}=2.5sec$

We know that voltage across capacitor is given by $v_c=v_s(1-e^{\frac{-t}{\tau }})$

$v_c=50(1-e^{\frac{-5}{2.5 }})=43.2332v$

So current will be $=\frac{v_s-v_c}{R}=\frac{50-43.2332}{25\times 10^{-6}}=0.2706\times 10^6A$

So current through circuit will be $0.2706\times 10^6A$

4 0

4 years ago

Bernie drove home from a vacation in 1.5 hours. He traveled a total distance of 60 miles. What was his average speed in miles pe

mafiozo [28]

Answer: 40

Explanation:

I believe this is correct. I did 60/1.5 to get 40/mph

6 0

4 years ago

Read 2 more answers

A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu

Oduvanchick [21]

Answer:

It's Momentum becomes 4

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4 years ago

If it has enough kinetic energy, a molecule at the surface of the Earth can "escape the Earth's gravitation", in the sense that

user100 [1]

Answer:

$K_E=mgr_E$

Explanation:

By conservation of energy, the sum of the kinetic and gravitational potential energies at the surface of the Earth must be equal than their sum at infinity, so we have:

$K_E+U_E=K_\infty+U_\infty$

$\frac{mv_E^2}{2}-\frac{GM_Em}{r_E}=\frac{mv_\infty^2}{2}-\frac{GM_Em}{r_\infty}$

Where $G=6.67\times10^{-11}Nm^2/kg^2$ is the gravitational constant, $M_E=5.97\times10^{24}kg$ and $r_E=6371000m$ are the mass and radius of the Earth, <em>m </em>is the mass of the particle, $v_E$ its velocity at the surface of the Earth (which would be its escape velocity) and $v_\infty$ and $r_\infty$ are the velocities and distance at infinity, which would be null and infinity respectively, so the right hand side of our equation is 0J, which leaves us with:

$\frac{GM_Em}{r_E}=\frac{mv_E^2}{2}=K_E$

Also, since the force the molecule experiments is the force of gravity (disregarding drag), we can write its weight in terms of Newton's Law of Gravitation:

$F=mg=\frac{GM_Em}{r_E^2}$