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d1i1m1o1n [39]
3 years ago
10

2 over 3 is it theater than 7 over 8

Mathematics
2 answers:
AysviL [449]3 years ago
6 0
I think you mean greater than but 7/8 is greater than 2/3
EastWind [94]3 years ago
5 0
I believe you mean "greater" not "theater".

If this is true, than 7 over 8 is greater than 2/3.

Hope this helps! :)
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Line M contains points (4,3) and (1,2). Write a possible equation of line K that is
mash [69]
I believe the answer is y = -3x + 15
This is what I got from calculating it but I haven’t done this type of equation in a while
6 0
3 years ago
Find the distance between the points (-7.2, -9.3) and (-7.2, -1.1)
AlexFokin [52]

Answer:

8.2

Step-by-step explanation:

-7.2 to -7.2 is 0

-9.3 to -1.1 is 8.2

Pythagorean theorem is a^2+b^2=c^2

0^2=0

8.2^2=67.24

0+67.24=0

√67.24=8.2

The distance between the to points is 8.2

6 0
3 years ago
Use Gaussian elimination to write each system in triangular form
Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

  1. Swapping two rows
  2. Multiplying a row by a nonzero number
  3. Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]

For this matrix we need to perform the following row operations:

  • R_2 - 1 R_1 \rightarrow R_2 (multiply 1 row by 1 and subtract it from 2 row)
  • R_3 + 1 R_1 \rightarrow R_3 (multiply 1 row by 1 and add it to 3 row)
  • R_4 - 1 R_1 \rightarrow R_4 (multiply 1 row by 1 and subtract it from 4 row)
  • R_2 \leftrightarrow R_3 (interchange the 2 and 3 rows)
  • R_2 / 2 \rightarrow R_2 (divide the 2 row by 2)
  • R_1 - 1 R_2 \rightarrow R_1 (multiply 2 row by 1 and subtract it from 1 row)
  • R_4 - 1 R_2 \rightarrow R_4 (multiply 2 row by 1 and subtract it from 4 row)
  • R_3 \cdot ( -1) \rightarrow R_3 (multiply the 3 row by -1)
  • R_2 - 1 R_3 \rightarrow R_2 (multiply 3 row by 1 and subtract it from 2 row)
  • R_4 + 3 R_3 \rightarrow R_4 (multiply 3 row by 3 and add it to 4 row)
  • R_4 / 4.5 \rightarrow R_4 (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

If you later perform the following operations you can find the solution to the system.

  • R_1 + 0.5 R_4 \rightarrow R_1 (multiply 4 row by 0.5 and add it to 1 row)
  • R_2 + 0.5 R_4 \rightarrow R_2 (multiply 4 row by 0.5 and add it to 2 row)
  • R_3 - 2 R_4 \rightarrow R_3(multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

Thus, the solution is:

x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

7 0
3 years ago
Can you please help me on this it says fully simplify using only positive exponents 5x8y7/25x4y
dangina [55]

Answer:

1/5x^12 * y^8.

Step-by-step explanation:

((5x^8*y^7/25)x^4)(y)

=1/5x^12 * y^8.

4 0
2 years ago
A store has caps on display. Five of the caps are red. There are 4 more blue caps than green caps. There are 3 fewer yellow caps
Anton [14]
R=5
B=4+G
Y=G-3
R+B+Y+G=24
(5)+(4+G)+(G-3)+G=24
5+4+G+G-3+G=24
3G+6=24
3G=18
G=6
B=4+(6)
B=10
Y=(6)-3
y=3
answer
R+B+Y+G=24
5+10+3+6=24
8 0
3 years ago
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