Brad and matt are working in the lab.they noticed that when they mixed two dilute solutions together,the reaction between them h
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The rate of Formation of Carbocation mainly depends on two factors'
1) Stability of Carbocation:
The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.
2) Ease of detaching of Leaving Group:
The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,
R-I > R-Cl > R-F
B > C > A
1) Stability of Carbocation:
The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.
2) Ease of detaching of Leaving Group:
The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,
R-I > R-Cl > R-F
B > C > A
Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole
Explanation :
First we have to calculate the specific heat calorimeter.
Formula used :
where,
Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g
m = mass of benzoic acid = 0.235 g
c = specific heat of calorimeter = ?
= change in temperature =
Now put all the given value in the above formula, we get:
Thus, the specific heat of calorimeter is
Now we have to calculate the heat of combustion of caffeine.
Formula used :
where,
Q = heat of combustion of caffeine = ?
c = specific heat of calorimeter =
= change in temperature =
Now put all the given value in the above formula, we get:
Now we have to calculate the moles of caffeine.
Mass of caffeine = 0.275 g
Molar mass of caffeine = 194.19 g/mole
Now we have to calculate the heat of combustion per mole of caffeine at constant volume.
Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole
<u>Answer:</u>
<em>Actual temperature for the given temperature with thermometer with error of 6.5% is 63.8 degrees.</em>
<u>Explanation:</u>
The percentage error in thermometer is 6.5% this means that if the temperature is 100 degrees the thermometer shell show 106.5 degrees. now calculating the <em>actual temperature of the thermometer when the given temperature is 68°</em>
<em>Applying unitary method for solution 106.5</em>
Then 100 will be
=
= <em>63.8 Degrees</em>
<em>On solving the value of this equation will give the actual temperature as 63.8 Degrees .</em>