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3 years ago

? Question

Chemistry

1 answer:

mr_godi [17]3 years ago

6 0

A is the answer

In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place

dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the

outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons

identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate

the presence of two valence electrons

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A bottle of concentrated aqueous sulfuric acid, labeled 98.0 wt% h2so4, has a concentration of 18.0 m. (a) how many milliliters

nadya68 [22]

n this order, Ď=1.8gmL, cm=0.5, and mole fraction = 0.9 First, let's start with wt%, which is the symbol for weight percent. 98wt% means that for every 100g of solution, 98g represent sulphuric acid, H2SO4. We know that 1dm3=1L, so H2SO4's molarity is C=nV=18.0moles1.0L=18M In order to determine sulphuric acid solution's density, we need to find its mass; H2SO4's molar mass is 98.0gmol, so 18.0moles1Lâ‹…98.0g1mole=1764g1L Since we've determined that we have 1764g of H2SO4 in 1L, we'll use the wt% to determine the mass of the solution 98.0wt%=98g.H2SO4100.0g.solution=1764gmasssolutionâ†’ masssolution=1764gâ‹…100.0g98g=1800g Therefore, 1L of 98wt% H2SO4 solution will have a density of Ď=mV=1800g1.0â‹…103mL=1.8gmL H2SO4's molality, which is defined as the number of moles of solute divided by the mass in kg of the solvent; assuming the solvent is water, this will turn out to be cm=nH2SO4masssolvent=18moles(1800â’1764)â‹…10â’3kg=0.5m Since mole fraction is defined as the number of moles of one substance divided by the total number of moles in the solution, and knowing the water's molar mass is 18gmol, we could determine that 100g.solutionâ‹…98g100gâ‹…1mole98g=1 mole H2SO4 100g.solutionâ‹…(100â’98)g100gâ‹…1mole18g=0.11 moles H2O So, H2SO4's mole fraction is molefractionH2SO4=11+0.11=0.9

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3 years ago

The picture below shows a sample from a tree. What kind of tree is this?

HACTEHA [7]

Answer:

I believe it is Spruce, because of the shape of the leaves

7 0

3 years ago

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Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

MAVERICK [17]

Answer: The percent yield of water is 46.9 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For sulfuric acid:

Given mass of sulfuric acid = 72.6 g (Assuming)

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol$

For NaOH:

Given mass of NaOH = 77 g (Assuming)

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{77g}{40g/mol}=1.925mol$

The chemical equation for the reaction of sulfuric acid and sodium hydroxide follows:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of water

0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

$1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.67g$

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 12.5 g (Assuming)

Theoretical yield of water = 26.67 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{12.5g}{26.67g}\times 100\\\\\% \text{yield of water}=46.9\%$

Hence, the percent yield of water is 46.9 %

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3 years ago

Anthony's homework assignment is to demonstrate that an orange has already undergone a chemical change. Which of the following

wolverine [178]

B. Rotten orange is the correct answer. Hope this helps!

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4 years ago

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Write the formula for the salts that are oxidizing agents in chlorine bleaches

Stella [2.4K]

Answer:- NaClO(sodium hypochlorite) and $Ca(ClO)_2$ (calcium hypochlorite) are the salts that are oxidizing agents in chlorine bleaches.

Explanations:- NaOCl reacts with water to form hypochlorous acid(HOCl) that works as a bleach as it could remove the color of the objects.

Hypochlorite ion can also produce chlorine ion and oxygen which also works as a bleach.

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3 years ago

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