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Gennadij [26K]
3 years ago
9

Simple syrup is made by dissolving sugar in water. If you combine 8 ounces of hot water with 4 ounces of sugar to create a simpl

e syrup, what would you expect the syrup to weigh? Why?
Chemistry
1 answer:
Alina [70]3 years ago
6 0

Answer:

no comment I'm sow sorry

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Name the following aldehyde:
PIT_PIT [208]

The name of the aldehyde is 4, 7- diethyldecanal (D)

<h3>What are rules for naming organic compounds?</h3>

The rules for naming organic compounds are;

  1. Find the longest carbon chain in the compound. ...
  2. Name the longest carbon chain found
  3. Figure the ending name
  4. Then number the carbon atoms
  5. Name the side groups
  6. Then put the side groups in alphabetical order.

The longest chain of the structure given is 10 (deca)

It is an alkanal due to the presence of the carbonyl -CHO

There are two side groups (ethyl) at the 4th and 7th carbon atoms which are both the same, CH2CH3 and are named diethyl

Thus, the name of the aldehyde is 4, 7- diethyldecanal

Learn more about naming of organic compounds here:

brainly.com/question/14094007

#SPJ1

3 0
2 years ago
An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
zheka24 [161]

Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

Option A: negative, positive

Option B: negative, negative

Option C: positive, positive

Option D: positive, negative

Answer:

Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

ΔG = ΔH - TΔS

free energy is the energy available to do work. Thus, if a particular reaction is accompanied by a release of usable energy (that is, <u>ΔG is negative</u><u>), it is said to be</u><u> exergonic</u>. On the other hand, if a reaction consumes energy (that is, <u>ΔG is positive</u><u>), it is said to be </u><u>endergonic</u>.

Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

ΔG = ΔH - TΔS

           -        -

This means that the reaction proceeds spontaneously at low temperatures. At high temperatures, the reverse reaction becomes spontaneous. An example of that would be the following reaction:

NH₃(g) + HCl(g) → NH₄Cl(s)

4 0
3 years ago
Given the equation representing a solution equilibrium: BaSO4(s) &lt;—&gt; Ba2+ (aq) + SO4 2- (aq)
goldenfox [79]

Answer:

The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases

Explanation:

Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.

In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;

BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.

This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.

3 0
3 years ago
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

3 0
3 years ago
Read 2 more answers
Electron configuration of br-1
lubasha [3.4K]

Answer:

Hi myself Shrushtee

Explanation:

The electron configuration of Br- is [Ar] 3d10 4s2 4p6

hope it will help you

please mark me as brainleist and follow

5 0
3 years ago
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