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Elenna [48]
3 years ago
6

Christina wants to compute the cost of tiling the floor in her bathroom. The floor measures 7 feet 6 inches by 8 feet 10 inches.

Each tile covers 1 square foot. —A box of 45 tiles costs $35.95.
(Christina is buying 2 boxes)

What is the cost of the tile needed for this project?



I got an answer of $71.9. Is that correct?
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

Two boxes will cost \$35.95\cdot 2=\$71.9. The cost of one tile is approximately \dfrac{\$71.9}{67}\approx \$1.08.

Step-by-step explanation:

Note that 1 ft = 12 in, then

7\ ft\ 6\ in=7\cdot 12+6\ in =90\ in,\\ \\8\ ft\ 10\ in=8\cdot 12+10\ in=106\ in.

The area of the floor is

90\cdot 106=9540\ in^2.

Now

1\ ft^2=144\ in^2,

then

144 sq. in - 1 tile,

9540 sq. in - x tiles.

Mathematically,

\dfrac{144}{9540}=\dfrac{1}{x},\\ \\x=\dfrac{9540}{144}=66.25

tiles is needed to cover the floor (67 full tiles).

Each box of tiles contains 45 tiles, so Cristina has to buy 2 boxes. These two boxes will cost \$35.95\cdot 2=\$71.9. The cost of one tile is approximately \dfrac{\$71.9}{67}\approx \$1.08.

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