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denis-greek [22]
3 years ago
8

Prove the converse of the Pythagorean theorem using similar triangles. The converse of the Pythagorean theorem states that when

the sum of the squares of the links of the legs of the triangle equals the shared length of the hypotenuse, the triangle is a right triangle. Be sure to create and name the appropriate geometric figures. HELPPP

Mathematics
2 answers:
liraira [26]3 years ago
8 0

Answer:

Step-by-step explanation:By AA similarity postulate

△ADB∼△ABC∼△BDC

therefore the sides of the triangles are proportional, in particular

ADAB=ABAC ACBC=BCDC

By algebra we have the following equations

AD⋅AC=AB⋅ABAC⋅DC=BC⋅BC

this is the same as

AD⋅AC=AB2AC⋅DC=BC2

"Equals added to equals are equal" allows us to add the equations

AD⋅AC+AC⋅DC=AB2+BC2

By distributive property

AC(AD+DC)=AB2+BC2

but by construction AD+DC=AC.

Substituting we have

AC⋅AC=AB2+BC2

this is equivalent to

AB2+BC2=AC2

which is what we wanted to prove

Whitepunk [10]3 years ago
5 0

Answer:

I don't how to exactly put the explanation in words I hope this helps you

Step-by-step explanation:

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Use the distributive property for this expression: 6(2x+5y)
posledela
(6 times 2x) + (6 times 5y)

5 0
3 years ago
F(x)=x+2/2 what is the value of f(-8)<br><br> A.-4<br> B.-3<br> C.-5<br> D.-6
bonufazy [111]
Answer: Choice B) -3

------------------------------------------------------

Work Shown:

f(x) = (x+2)/2
f(-8) = (-8+2)/2 ... replace every x with -8; use PEMDAS
f(-8) = (-6)/2
f(-8) = -3

4 0
3 years ago
. If α and β are the roots of
Lostsunrise [7]

Answer:

18x^2+85x+18 = 0

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> 2x^2+7x-9=0

Comparing it with ax^2+bx+c = 0, we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = -\frac{b}{a}

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = \frac{\alpha }{\beta } + \frac{\beta }{\alpha }

Sum of Roots = \frac{\alpha^2+\beta^2  }{\alpha \beta }

Sum of Roots = \frac{(\alpha+\beta )^2-2\alpha\beta   }{\alpha\beta  }

Sum of roots = (\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}

Sum of roots = \frac{49}{4} + 9 /\frac{-9}{2}

Sum of Roots = \frac{49+36}{4} / \frac{-9}{2}

Sum of roots = \frac{85}{4} * \frac{2}{-9}

Sum of roots = S = -\frac{85}{18}

Product of Roots = \frac{\alpha }{\beta } \frac{\beta }{\alpha }

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> x^2-Sx+P = 0

=> x^2 - (-\frac{85}{18} )x+1 = 0

=> x^2 + \frac{85}{18}x + 1 = 0

=> 18x^2+85x+18 = 0

This is the required quadratic equation.

5 0
3 years ago
Read 2 more answers
5k+ 3 &lt;-32 or -4k+ 7 &lt;-29
inessss [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can you help me please?
ExtremeBDS [4]

Answer:

0≤x≤8

Step-by-step explanation:

the domain is basically all the x-values that are applicable to the graph.

Here we can clearly see that the graph starts at x = 0 and ends at x = 8. There are no other possible x-values which is applicable to the graph,

hence the domain is 0≤x≤8

6 0
3 years ago
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