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ddd [48]
3 years ago
13

Specific gravity of a vegetable oil is 0.85. What is its density?

Chemistry
1 answer:
elena-s [515]3 years ago
6 0
I think its density is 850kg/m^3
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Potassium is isotopic and has RAM of 39.5 work out the percentage abundance of each isotope in a given sample of potassium which
Troyanec [42]

Yo sup??

Let the percentage of K-39 be x

then the percentage of K-40 is 100-(x+0.01)

We know that the net weight should be 39.5. Therefore we can say

(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5  

(since we are taking it in percent)

39*x+40*(100-(x+0.01))+38*0.01=3950

39x+4000-40x-0.4+0.38=3950

2x=49.98

x=24.99

=25 (approx)

Therefore K-39 is 25% in nature and K-40 is 75% in nature.

Hope this helps.

3 0
3 years ago
Nts
a_sh-v [17]

The reaction is a synthesis reaction.

<h3>What are synthesis reactions?</h3>

Synthesis reactions are one of the numerous reactions in chemistry. These kinds of reactions involve the combination of two atoms of different elements resulting in the formation of new compounds.

Synthesis reactions are sometimes referred to as combination reactions, simply because they have to do with the combination of two or more atoms of different elements into a single compound.

The different elements that combine are referred to as the reactants while the result of the combination is known as the product.

For example: A + B --> AB

In the illustrated reaction, N2 combined with H2 to form NH3. N2 and H2 gases are the reactants while NH3 is the only product formed from the two reactants.

This is a good example of a synthesis/combination reaction.  

More on synthesis reactions can be found here: brainly.com/question/24936069

#SPJ1

6 0
2 years ago
10) How many grams are there in 1.00 x 10^24 molecules of BC13?
lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have \frac{1}{6.022*10^{23} } moles.

So 1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles

grams of BCl_{3}=117.17*1.66=194.5 g

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

3 0
3 years ago
What type of plate boundary would form where there is a mountain range present, known earthquake activity, but no trenches prese
Natasha_Volkova [10]

Answer:

continental-continental convergent boundary

Explanation:

When two continental plates converge, they smash together and create mountains. The amazing Himalaya Mountains are the result of this type of convergent plate boundary. The Appalachian Mountains resulted from ancient convergence when Pangaea came together.

5 0
3 years ago
A certain hydrocarbon has a molecular formula of C9H16. Which of the following is not a structural possibility for this hydrocar
snow_tiger [21]

Answer: Option (d) is the correct answer.

Explanation:

It is given that molecular formula is C_{9}H_{16}. Now, we will calculate the degree of unsaturation as follows.

Degree of unsaturation = C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1

                                  = 9 - \frac{16}{2} + 1

                                  = 9 - 8 + 1

                                  = 2

As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.

Yes, this compound could be an alkyne as for alkyne D.B.E = 2.

But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.

Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.

6 0
4 years ago
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