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Alika [10]
4 years ago
10

A copper wire is stretched so that its length increases and its diameter decreases. As a result:

Physics
1 answer:
slava [35]4 years ago
3 0

Answer: A) False; B) False; C) True; D) False

Explanation: In order to explain this problem we have to take into account the expresion of the resistence of the condutor wire, which os given by:

R=ρ*L/A where ρ, L and A are the resistivity, length and area of the conductor.

As it can be seen, the resitence is inverse to the area so when the diameter decrease the resistance should increase its value. (A, C).

The resistivity does not depend on the length or diameter of the wire, only it depends on the material use to made the wire.  (B,C and D).

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3.86×10⁶ Newton/coulombs

Explaination:

Applying,

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Where E = Electric Field, F  = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

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