Complete Question
Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail
Answer:

Explanation:
From the question we are told that:
Mass 
Initial Velocity 
Distance 
Diameter 
Length 
Generally the equation for Force is mathematically given by



Answer:
ΔV = -0.97 m³/ kg
ΔH = 0 kJ/ kg
Explanation:
<u>To determine the change in the </u><u>specific volume</u><u> we need to </u><u>use the ideal gas law</u><u>:</u>
<em>where</em><em> P</em><em>: </em><em>pressure </em><em>of the gas </em><em>V</em><em>: </em><em>volume </em><em>of the gas, </em><em>R</em><em>: i</em><em>deal gas constant</em><em>= 0.4119 kJ/kg.K = 0.4119 kPa.m³/kg.K and </em><em>T</em><em>: </em><em>temperature </em><em>of the gas.</em>
<u />
<u>The </u><u>V₁,</u><u> at a compressed pressure is:</u>


<u>Similarly, the </u><u>V₂</u><u> is:</u>


Now, the change in the specific volume because the compressor is:

Finally, to calculate the change in the specific enthalpy, we need to remember that neon is an ideal gas and that is an isothermal process:
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