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Nezavi [6.7K]
3 years ago
6

What questions, if we were to answer them, would

Chemistry
1 answer:
Margarita [4]3 years ago
7 0

Answer:

When our bodies are dry and wind blows by, we lose some energy to the air molecules. When are bodies are wet, we have a substance on our skin that likes to absorb heat. So when wind blows by, we lose a LOT of energy to the air molecules. When the body loses heat energy, our body temperature drops.

Explanation:

hope it helps

<u>plzz </u><u>mark</u><u> it</u><u> as</u><u> brainliest</u><u>.</u><u>.</u><u>.</u>

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When sound molecules "stack up" in front of high-speed flights, what could
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pretty sure its B thank me later

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3 years ago
Determine the number of grams in each of the quantities<br><br> 1.39.0 x 1024 molecules Cl2
STatiana [176]

Mass of Cl₂ : 164.01 g

<h3>Further explanation</h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol Cl₂ :

\tt n=\dfrac{N}{No}\\\\n=\dfrac{1.39.10^{24}}{6.02.10^{23}}\\\\n=2.31

mass Cl₂(MW=71 g/mol) :

\tt mass=mol\times MW\\\\mass=2.31\times 71=164.01

8 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

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3 years ago
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Use gloves so your nails wont puncture it and because its soft
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Beth pushes a box with a force of 2 N to the left. Dave pushes the same box from the opposite side with a force of 8 N to the ri
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Answer:

is this based on the newtons law and balnce force

Explanation:

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