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Nezavi [6.7K]
2 years ago
6

What questions, if we were to answer them, would

Chemistry
1 answer:
Margarita [4]2 years ago
7 0

Answer:

When our bodies are dry and wind blows by, we lose some energy to the air molecules. When are bodies are wet, we have a substance on our skin that likes to absorb heat. So when wind blows by, we lose a LOT of energy to the air molecules. When the body loses heat energy, our body temperature drops.

Explanation:

hope it helps

<u>plzz </u><u>mark</u><u> it</u><u> as</u><u> brainliest</u><u>.</u><u>.</u><u>.</u>

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Science 10 workbook
Kruka [31]

Answer:

for more details are in the pic

4 0
3 years ago
I need help what is s-1/3=7/9???? please help guys and thank you
nalin [4]

Answer:

10/9

Explanation:

First, let's convert 1/3 and 7/9 so that the have the same denominator. To do this let's find the least common multiple of 3 and 9.

List the multiples of 3 and 9:

3: 3, 9

9: 9

They have a least common multiple of 9

We need to convert 1/3 so it has a denominator of 9:

1/3*3/3 (we can multiply it by 3/3 because any number over itself is 1) = 3/9

s-3/9=7/9

Add 3/9 to both sides to isolate s

s=10/9

6 0
2 years ago
The enthalpy of combustion of gasoline (C8H18) is 5471 kJ mol-1. How much heat will be produced by burning 1 gallon of gasoline
kvv77 [185]

Answer:

127529 KJ

Explanation:

Since 1gallon = 3.78 L= 3780 ml

The density of C8H18= 0.703 g/mL

Density = mass/volume

Mass= Density × volume

Mass= 0.703 g/mL × 3780 ml

Mass= 2657.34 g

Molar mass of C8H18= 114 g/mol

Number of moles= mass/molar mass

Number of moles= 2657.34/114

Number of moles= 23.31 moles

Since 1 mole evolved=5471 kJ

23.31 moles = 5471 kJ × 23.31 = 127529 KJ

8 0
2 years ago
¿En qué grupo de sustancias químicas se incluye a la Hemoglobina?
olga2289 [7]

Answer:

"HEMOGLOBINA. Las características de la hemoglobina (Hb) como amortiguador están íntimamente vinculadas a la capacidad de disociación del grupo imidazólico del aminoácido histidina unido al hierro que contiene el grupo hemo (ver figura inferior)."

Link: http://www.ehu.eus/biomoleculas/buffers/buffer4.htm#:~:text=HEMOGLOBINA&text=Las%20caracter%C3%ADsticas%20de%20la%20hemoglobina,hemo%20(ver%20figura%20inferior).

3 0
2 years ago
HELP . Read the following graduated cylinder.
Anon25 [30]

The volume of the liquid from the graduated cylinder is 22.5 mL

The last option (22.5 mL) is the correct option

The question seems to be incomplete

The image that completes the question is shown in the attachment below.

From the image, we observe that the liquid meniscus is between the 20 mL and 25 mL marks. That means the volume will lie in this range.

NOTE: The meniscus of a liquid is the upward or downward curve seen at the top of a liquid in a container.

The type of curve shown in the image is a concave meniscus and the volume of the liquid is read from the bottom of the curve.

To read the value from the graduated cylinder, we will first determine the difference between two consecutive lines. Between the 20 mL and 25 mL mark (two thick lines), we have 5 spaces separated by thin lines.

The measure between two consecutive lines is the difference between two thick lines divided by number of spaces between them

∴ The measure between two consecutive lines = (25mL - 20mL) ÷ 5

The measure between two consecutive lines = 5mL ÷ 5 = 1 mL

Now, to read the position of the liquid,

Starting from the 20 mL mark, the liquid exceeds two more lines + half way to the next line ( that is 2mL + 0.5 mL)

∴ The position of the liquid is 20 mL + 2mL + 0.5 mL = 22.5 mL

Hence, the volume of the liquid from the graduated cylinder is 22.5 mL

Learn more here: brainly.com/question/19240870

3 0
2 years ago
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