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3 years ago

What questions, if we were to answer them, would

Chemistry

1 answer:

Margarita [4]3 years ago

7 0

Answer:

When our bodies are dry and wind blows by, we lose some energy to the air molecules. When are bodies are wet, we have a substance on our skin that likes to absorb heat. So when wind blows by, we lose a LOT of energy to the air molecules. When the body loses heat energy, our body temperature drops.

Explanation:

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Why is pure silicon a poor conductor at room temperature brainly

trapecia [35]

Pure silicon is a poor conductor at room temperature because it has 4 valence electrons

4 0

3 years ago

A 5 L tank of oxygen with a pressure of 23 atm is moved from room temperature of 293 K to a storage freezer at 230 K. What is th

storchak [24]

Answer: The final pressure inside the tank will be B. 18.05 atm. Gay-Lussac's law is used to predict the changes in pressure or temperature of gases. According to this law, there is a direct relationship between pressure and temperature. As the temperature of gas increases, so, too, will the pressure increase and vice versa.

Further Explanation:

We use the mathematical expression of Gay-Lussac's law to find the final pressure in the tank:

$\frac{P_{initial}}{T_{initial}} \ = \frac{P_{final}}{T_{final}}$

It is very important to note that when using this equation, all temperatures must be expressed in Kelvin. The conversion from degree Celsius to Kelvin is:

$T \ (in \ K) \ = T \ (in \ deg.\ C) \ +\ 273.15$

In the problem, we are given the following information:

P(initial) = 23 atm

T(initial) = 293 K

P(final) = ?

T(final) = 230 K

Plugging in these values in the Gay-Lussac Equation, we get:

$\frac{23\ atm}{293 \ K} \ = \ \frac{P_{final}}{230\ K} \\P_{final} \ = \frac{(23 \ atm) \ (230 \ K)}{293 \ K}\\P_{final} \ = \ 18.05 \ atm$

The tank was moved from a hotter to a cooler place. At cooler temperatures, gas particles move slower and frequency and strength of their collisions with each other and the wall of the containers decrease. This leads to a decrease in the pressure. Thus, the pressure drops from 23 atm to 18.05 atm when the tank is inside the freezer.

Learn More:

Learn more about Charles' Law brainly.com/question/7259721
Learn more about Ideal Gas Law brainly.com/question/4147359
Learn More about Boyle's Law brainly.com/question/8511562

Keyword: Gas Pressure, Temperature, Gay-Lussac's Law

8 0

3 years ago

You need 180 mL of a 25% alcohol solution. On hand, you have a 30% alcohol mixture. How much of the 30% alcohol mixture and pure

svetlana [45]

Answer:

150 mL of the 30% alcohol mixture and 30 mL of the pure water will we need to obtain the desired solution.

Explanation:

Let the volume of 30% alcohol used to make the mixture = x L

For 25% alcohol:

C₁ = 25% , V₁ = 180 mL

For 30% alcohol :

C₂ = 30% , V₂ = x L

Using

C₁V₁ = C₂V₂

25×180 = 30×x

So,

x = 150 mL

Pure water = 180 mL - 150 mL = 30 mL

150 mL of the 30% alcohol mixture and 30 mL of the pure water will we need to obtain the desired solution.

7 0

3 years ago

What is the bond order of c2−?express the bond order numerically?

diamong [38]

MO Diagram of C₂⁻ is shown below,

Bond order is calculated as,

Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,

BMO = Bonding Molecular Orbital

ABMO = Anti-Bonding Molecular Orbital

Putting values,

Bond Order  =  [9]-[4] / 2

Bond Order  =  5 / 2

Bond Order  =  2.5