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Scorpion4ik [409]
3 years ago
9

10. How much protein one should obtain from diet (1 gram, 3 gram,4gram)

Chemistry
2 answers:
jarptica [38.1K]3 years ago
7 0

How much protein one should obtain from diet

Answer:

4 gram

VikaD [51]3 years ago
5 0

Answer:

4grammes

Explanation:

You might be interested in
Which of these expressions are correct variations of the Combined Gas Law?
mafiozo [28]

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

              PV  = nRT

 and then;

                  \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

   If we cross multiply;

                P₁V₁T₂   = P₂V₂T₁

  So;

         T₁ = T_{2} \frac{P_{1}V_{1}  }{P_{2} V_{2} }

Also;

         V₂  = V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }

So from the choices both are correct

3 0
2 years ago
35. In the collision theory, a collision that leads to the formation of products is called an
FinnZ [79.3K]

Answer:

It's Effective Collision.

Explanation:

Hope my answer has helped you!

7 0
3 years ago
Please help.This is due tomorrow.It's worth 2 grades.Please help.God bless u.Please and thankyou so much.
Daniel [21]

Answer:

1. False - compression

2. True

3. False - transform faults

4. False - horizontally

5. True

6. False- perpendicular

7. False - away from

8. False - increase

9. True

10. True

Explanation:

1. Mountains, oceanic trenches, and rift valleys are created by tension and compression stress. They are formed by divergent and convergent boundaries. Compression stress occurs when plates are pushing against each other, while tension stress occurs when the plates are pulling away from each other.

**Shear stress happens when the plates grind against each other. Often found in transform boundaries.

2. Transform faults happen when two plates glide or slide against each other. These areas are called transform boundaries. Transform faults occur in the ocean. When these boundaries are formed on land, they are called strike-slip faults.

3. Shear stress that occur in transform boundaries produce transform faults. These faults are usually identified by long faults and ridges. Sometimes small ponds form in the cracks due to deposition.

*** Rift valleys are produced by divergent boundaries or tension stress, when the plates are pulled apart.

4. Transform boundaries are formed when two plates slides against each other. Transform faults are formed in these boundaries and the movement of the plates are horizontal.

*** They do not move vertically.

5-6. Mid-oceanic ridges are segmented or divided by transform faults. The transform faults in the mid-oceanic ridges are perpendicular to the oceanic ridges. They separate them into distinct segments and can run across for hundreds of kilometers

7. New faults form as they move away from the ridges. Mid oceanic ridges are formed when the plates move apart, pushing the seafloor outwards and along with that, the transform faults. When new crust however overlaps the transform fault, they stop moving against each other, and start moving side by side, creating a crack.

8. Transform faults increase in size as long as the plates continue to move. The areas of transform faults, especially in the surface create earthquake faults.

9. Faults at the surface can be part of a larger underground system. Some faults can cut across continental crusts. These faults are created by different geological processes, like compression stress from convergent boundaries, tension stress from divergent boundaries, and shear stress from transform boundaries.

10. Fault zones are areas where you can find different faults formed, relatively close to each other. The faults in fault zones can be shallow or deeper like the fault zone Sierra Madre.

6 0
3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
an unknown amount of mercury (ii) oxide was decomposed in the lab. mercury metal was formed and 4.50 l of oxygen gas was release
Assoli18 [71]

The initial weight of mercury oxide in the sample was 59.1 g HgO.

<h3>Steps</h3>

chemical reaction

2HgO ⟶ 2Hg + O₂

the moles of O₂

pV = nRT

n = (pV)/(RT)

Data:

p = 0.970 atm

V = 4.50 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 390.0 K

Calculation:

n = (0.970 × 4.500)/(0.082 06 × 390.0)

n = 0.1364 mol O₂

the moles of HgO

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

the mass of HgO

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = 59.1 g HgO

<h3>What is the name of HgO?</h3>

For the creation of various organic mercury compounds and specific inorganic mercury salts, mercury(II) oxide, or HgO, serves as a source of elemental mercury.

This red or yellow crystalline substance is also utilised in mercury batteries and zinc-mercuric oxide electric cells as an electrode (combined with graphite).

<h3>What is the purpose of mercury oxide?</h3>

Mercuric oxide is a colourless, crystalline powder that ranges from yellow to orange-yellow.

It serves as a seed protectant, a pigment, a preservative, and an ingredient in alkaline batteries and cosmetics.

<h3>Is there a combination of mercury oxide?</h3>
  • The powder form of mercury oxide is dark black or dark brown.
  • An intimate blend of metallic mercury and mercuric oxide rather than a genuine compound.

learn more about mercury oxide here

brainly.com/question/3235037

#SPJ4

4 0
1 year ago
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