Answer:
For the first oxide, 1 g gives 0.888 g of copper.
Dividing by 0.888 tells us that 1.126 g gives 1 g of copper so has 0.126 g of oxygen.
For the second oxide, 1 g gives 0.798 g of copper.
Dividing by 0.798 tells us that 1.253 g gives 1 g of copper so has 0.253 g of oxygen.
So 1 g of copper combines with either 0.126 g or 0.253 g of oxygen.
Within the limits of experimental error, 0.253 is twice 0.126, confirming the law of multiple proportion.
Answer:
1 : 2
Explanation:
From the question given, we obtained the following information:
T1 = 287°C = 287 +273 = 560K
T1 = 587°C = 587 +273 =860K
V1 = V
V2 =?
V1 /T1 = V2 /T2
V/560 = V2/860
Cross multiply
V2 x 560 = 860 x V
Divide both side by 560
V2 = (860 x V) / 560
V2 = 1.54V = 2V
The ratio of initial to final volume =
V1 : V2
= V : 2V
= 1 : 2
31
A dalton is the same as an atomic mass unit. And an atomic mass unit is approximately the mass of a nucleon (proton or neutron) such that the mass is 1 g/mol. So in this problem you have 15 protons and 16 neutrons, so the number of daltons is 15 + 16 = 31.
Molarity (m) is defined as the number of moles to solute (n) the volume (v) of the solution in liters is important to note that the molarity is defined as moles of solute per liter of solution not moles of solute per liter of solute.
