<h2>Let us complete it :</h2>
Explanation:
let us study about formation of sodium phosphide
Electrons are transferred from atoms of sodium to atoms of phosphorous
The sodium atom looses electrons and the phosphorus atoms
gains electrons .
C. This transfer makes the sodium atoms acquire positive charge and phosphorous acquire negative charge .
As a result, the sodium and phosphorus atoms strongly bond with
each other.
Answer is: the percent composition of Hg in the compound is 71.5%.
Balanced chemical reaction: Hg + Br₂ → HgBr₂.
m(Hg) = 60.2 g; mass of the mercury.
m(Br₂) = 24.0; mass of the bromine.
m(HgBr₂) = m(Hg) + m(Br₂).
m(HgBr₂) = 60.2 g + 24 g.
m(HgBr₂) = 84.2 g; mass of the compound.
ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.
ω(Hg) = 60.2 g ÷ 84.2 g · 100%.
ω(Hg) = 71.5%.
In a dilute acid solution most if not all of the molecules will split into ions.
For example HCl is a strong acid and 100% of the molecules will split into
H+ & Cl-
in a weak acid solution only a portion of the molecules will turn into ions because the ionization percentage isn't as large. Which will essentially leave a high percentage of un-reacted molecules
