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Nastasia [14]
2 years ago
6

Estimate the sum or difference of 23/40 11/30

Mathematics
2 answers:
irinina [24]2 years ago
6 0

Answer:


Step-by-step explanation:


Vinvika [58]2 years ago
5 0
1 my nikka
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June has a savings account with an annual simple interest rate of 2.6%. She hopes to gain $6,500 in interest over a period of el
leonid [27]
\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$6500\\
P=\textit{original amount deposited}\\
r=rate\to 2.6\%\to \frac{2.6}{100}\to &0.026\\
t=years\to &3
\end{cases}

she should have invested P, in order to get I = 6500

but she instead invested 17,801, how much more did she need? well, P - 17801

solve for P
7 0
3 years ago
Read 2 more answers
Point A is located at (5, 10) and point B is located at (20, 25).
Alla [95]
Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at  a ratio of 7, thus 3:7,

\bf \left. \qquad  \right.\textit{internal division of a line segment}
\\\\\\
A(5,10)\qquad B(20,25)\qquad
\qquad 3:7
\\\\\\
\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\
-------------------------------\\\\
{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\
-------------------------------

\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)
\\\\\\
C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10}  \right)
\\\\\\
C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2}  \right)
8 0
3 years ago
The cost for b, breakfasts, l, lunches, and d, dinners for a group of people is 6.5b + 9.757 + 17.25d. What is the total cost of
ira [324]

Answer:

417.084

Step-by-step explanation:

9*6.5+12*9.757+14*17.25

58.5+117.084+241.5

⇒417.084

5 0
3 years ago
Read 2 more answers
What is the greatest common factor of 16,32, and 44?
liubo4ka [24]
The greatest common factor of the three numbers is 4
4 0
3 years ago
I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?
stich3 [128]
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
7 0
3 years ago
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