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trapecia [35]
3 years ago
9

In an arithmetic sequence, find a6 when a1 = 13 and d = 4

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0

a_{6} = 33

the n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1 )d, hence

a_{6} = 13 + (5 × 4 ) = 13 + 20 = 33


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One number is 8 more than another number, and their sum is 20. Find the numbers.
melomori [17]

Answer:

First number=6

Second number=14

Step-by-step explanation:

Let the first number be x

So the second number is x+8

So the sum of the two is

X+x+8=20

2x+8=20

2x=20-8

2x=12

X=12/2

=6

The second number will x+8

So 6+8=14

First number=6

Second number=14

6 0
3 years ago
Read 2 more answers
Kenya has 2 hours to work a 100 problem math test. At what rate must she work in order to finish in 2 hours?
slavikrds [6]

What does this quote tell us about the media’s influence during the Nixon investigation?
 
"We saw the public man in his first administration, and we were impressed. Now in about 300,000 words we have seen the private man, and we are appalled." – Clayton Kirkpatrick, editor of the Chicago Tribune, a newspaper that published the entire transcript of Nixon’s released communications

  A. The media shared real evidence and their opinions on it, which probably influenced citizen opinion.  B. The media disapproved of the president’s private actions but still supported and re-elected him. C.The media rallied behind the president because of his great record during his first term in office.<span> D. The media could not publish or discuss real evidence related to the president or the investigation. please help me.</span>

<span>the answer for u is  </span>

<span>2 hours=120 minutes
You simply just do 120/100=1.2
So the answer is B. 1.23 or 1.2 (rounded) per minute</span>


4 0
3 years ago
Read 2 more answers
Solve this with the explanation please
nikitadnepr [17]
  1. yes,
  2. 301 times.

Hope it helps

8 0
2 years ago
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
2 years ago
Find the length of the indicated side.
Ne4ueva [31]

Hello

DEF and IKL , equilateral  =>

DE = 5x-12 = 3x-4

5x-3x= -4+12

2x= 8

x=4

DE = 5x-12 =  20-12 = 8

KL = 3x+24 = 10x+3

24 -3 = 10x-3x

21 = 7x

x= 21/7 = 3

KJ = 10x+3 = 30+3 = 33

6 0
3 years ago
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