We know that
The Standard Form<span> of a </span>Quadratic Equation<span> is
</span> ax²<span> + bx + c = 0
</span>
then
for x=0 y=-6
a*0² + b*0 + c = -6---------> c=-6
for x=1 y=2
a*1² + b*1 -6 = 2---------> a+b=8---------> a=8-b---------> equation 1
for x=3 y=-0
a*3² + b*3 -6 = 0---------> 9a+3b=6---------> equation 2
<span>substituting 1 in 2
9*(8-b)+3b=6------> 72-9b+3b=6---------> 6b=66--------> b=11
a=8-11-------> a=-3
so
a=-3
b=11
c=-6
</span>Standard Form of a Quadratic Equation is
-3x² + 11x - 6 = 0
<span>
the answer is
</span> -3x² + 11x - 6 = 0<span>
</span>
Answer:
D) 2x²+4x-30
Step-by-step explanation:
You would multiply x and 2x; x and -6; 5 and 2x; 5 and -6
(x)(2x) = 2x²
(x)(-6) = -6x
(5)(2x) = 10x
(5)(-6) = -30
Now just put it back in the order that it was listed in the equation starting with (x)(2x)
This would give you 2x²-6x+10x-30
Simplify even further to get 2x²+4x-30
*Sorry I messed up my math please read the new answer.
Use distrubitive property to get rid of parentheses. Multiply -3 by 4r and -8 to get -12r+24=36. Then zero out 24 by subtarcting 24 from both sides. You. should then have -12r=12. Divide by -12 on both sides to get r by itself. Your answer should be r=1*. Hope this helps :)
Answer:
9
Step-by-step explanation:
1, 3, 5, 9, 15, 19, 19
Answer:
☥ 
- Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).
☥ 
☪ 
- Slope ( m ) = -2
- Given point = ( - 1 , 8 )
☪ 
- Equation of a line in slope - intercept form ( i.e y = mx + c )
Let the point ( -1 , 8 ) be ( x₁ , y₁ )
☪ 
plug the known values :
↦ 
↦ 
Distribute -2 through the parentheses :
↦ 
Transpose 8 to right hand side and change it's sign
↦ 
↦ 
And we're done !
Hope I helped!
♡ Have a wonderful day / night ツ
~TheAnimeGirl ♪
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