Answer:
The correct answer is 16 gram per mole.
Explanation:
Let A be the gas helium, and B be the unknown gas. It is clearly mentioned in the question that the effusion rate of helium gas is two times more than that of gas B. The molar mass of helium is 4.0 gram per mole. To solve the problem, Grahm's law is used, that is,
Rate of effusion A/rate of effusion B = √ (Molar mass B/Molar mass of A
2.0 = √Molar mass of B/4.0 gram per mole.
Now squaring both the sides we get,
4.0 = Molar mass of B / 4.0
The molar mass of B = 16 gram per mole.
