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4 years ago

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How to reduce a ratio to lowest terms

2 answers:

aleksley [76]4 years ago

7 0

It is usual to represent ratios in their simplest form so that we are not operating with large numbers. Reducing ratios to their simplest form is directly linked to equivalent fractions.

For example: On a farm there are 4 Bulls and 200 Cows. Write this as a ratio in its simplest form.

Bulls <span>: </span>Cows

4 <span>: </span>200

If we halve the number of bulls then we must halve the number of cows so that the relationship between the bulls and cows stays constant. This gives us:

Bulls <span>: </span>Cows

2 <span>: </span>100

Halving again gives us

1 <span>: </span>50

So the ratio of Bulls to Cows equals 1 : 50. The ratio is now represented in its simplest form.

An example where we have 3 quantities.

On the farm there are 24 ducks, 36 geese and 48 hens.

Ratio of ducks <span>: </span>geese <span>: </span>hens

24 <span>: </span>36 <span>: </span>48

Dividing each quantity by 12 gives us

2 <span>: </span>3 : 4

So the ratio of ducks to geese to hens equals 2 : 3 : 4 which is the simplest form since we can find no further common factor.

Masja [62]4 years ago

5 0

The other brainly user explains this well but to sum up you just have to find the great common factor or reduce step by step with the factor you see.

Hope this helps !

Photon

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3 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is a re

Rudik [331]

Answer: $\dfrac{15}{17}$

Step-by-step explanation:

Total number of cards in a deck = 52

Number of red cards = 26

Number of cards not red =

Number of ways to draw not red cards = $^{26}C_3$

Total ways to draw 3 cards = $^{52}C_3$

The probability that none of three cards are red = $\dfrac{^{26}C_3}{^{52}C_3}$

$=\dfrac{\dfrac{26!}{3!(26-3)!}}{\dfrac{52!}{3!(52-3)!}}$ [∵ $^nC_r=\dfrac{n!}{r!(n-r)!}$ ]

$=\dfrac{\dfrac{26\times25\times24\times23!}{(23)!}}{\dfrac{52\times51\times50\times49!}{3!(49)!}}=\dfrac{2}{17}$

Now , the probability that at least one of the cards drawn is a red card = 1- Probability that none cards are red

$=1-\dfrac{2}{17}=\dfrac{17-2}{17}=\dfrac{15}{17}$

Hence, the required probability = $\dfrac{15}{17}$

6 0

3 years ago

A telephone costs 149.00$ , you receive a sale of 35%

SSSSS [86.1K]

35% of $149.00 is $52.15.

$149.00 - $52.15 = $96.85.

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3 years ago

Line e passes through points (10, 8) and (3, 5). Line f passes through points (3, 1) and (10, 4). Are line e and f parallel or p

babunello [35]

Answer:

e║f.

Step-by-step explanation:

1) the pointed vectors of the given lines are:

for line e: (3-10;5-8)=(-7;-3);

for line f: (10-3;4-1)=(7;3);

2) -7/7=-3/3=-1, it means the lines are parallel.

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2 years ago

Imani can pick forty bushels of apples in 15 hours. Bill can pick the same amount in 13 hours. Find how long it would take them

Delvig [45]

Answer:

6.96 hours.

Step-by-step explanation:

First, we need to find out the hour rate of bushels picked for each of them.

If Imani can pick 40 bushels in 15 hours, then he picks 40/15 = 8/3 bushes per hour.

If Bill can pick 40 bushels in 13 hours, then he picks 40/13 bushes per hour.

Working together, they pick: $\frac{8}{3} +\frac{40}{13}$ bushes per hour.

Let's simplify this expression:

$\frac{8}{3} + \frac{40}{13} = \frac{104+120}{39} = \frac{224}{39}$ = 5.74

Now we can use a rule of three

1 hour -------5.74

x hours ------40

Then,

x = 40 / 5.74 = 6.96

Therefore, it would take them 6.96 hours working together.

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4 years ago

Round 24,061,562 to the nearest 1,000 and 100,000

jenyasd209 [6]

Nearest 1,000 = 24,062,000

Nearest 100,000= 24,100,000

Hope its correct :)

6 0

3 years ago

Read 2 more answers