Answer:
The correct option is: a. Photosphere
Explanation:
Sun is the brightest star in the sky of our planet Earth and the principle component of the Solar System. It is a <u>gaseous object</u> that is made up of hot plasma and contributes 99.86% to the total mass of our Solar System.
<u>The Sun does not have a clearly defined surface.</u> The <u>visible surface of the Sun is known as the Photosphere</u>, which is the deepest visible portion of the Sun.
Well even though im not giving you the whole answer, Im going to tell you what to do in order for you to do it. The main thing you need to do is to determine the delta H and delta S for the reaction.<span>Then subtract the reactants from the products.
On eexample of this is: </span><span>Delta H = (-634.9(CaO)+-393.5(CO2)) - (-1207.6 (CaCO3)) = 179.2 kJ
</span><span>Do the same thing for Delta S but make sure you use the correct units. Delta S is in Joules so you may need to convert. Once you have those values, plug into the equation
</span><span>Delta G= Delta H - T * Delta S
</span>And you will get your result
hope this is very useful for you
To get the melting point of a solution so, we will use this formula:
ΔT = - mKf
when:
m is molality of the solution
Kf is cryoscopic constant of water = 1.86 C/m
and ΔT is the change in melting point (T2 - 0 °C)
so, now we need to calculate the molality to substitute:
when the molality = moles NaCl / Kg of water
and when moles NaCl = mass / molar mass
= 2.5 g / 58 g/mol
= 0.043 mol
∴ Kg water = volume *density /1000
= 230 mL * 1 g/mL / 1000
= 0.23 Kg
∴ molality = 0.043 / 0.23 =0.187 M
by substitution:
T2-0°C = - 0.187 * 1.86
∴T2 = - 0.348 °C
I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
