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Serjik [45]
3 years ago
13

Consider the following reaction:

Chemistry
1 answer:
bekas [8.4K]3 years ago
3 0
Well even though im not giving you the whole answer, Im going to tell you what to do in order for you to do it. The main thing you need to do is to determine the delta H and delta S for the reaction.<span>Then subtract the reactants from the products.
On eexample of this is: </span><span>Delta H = (-634.9(CaO)+-393.5(CO2)) - (-1207.6 (CaCO3)) = 179.2 kJ
</span><span>Do the same thing for Delta S but make sure you use the correct units. Delta S is in Joules so you may need to convert. Once you have those values, plug into the equation
</span><span>Delta G= Delta H - T * Delta S
</span>And you will get your result
hope this is very useful for you
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∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

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replacing in Ka:

⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)

⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

⇒ Ka = 4.76108

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