13.45 will be the answer
since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2
this will then be 10^2 + 9^2 = c^2
181=c^2
c=13.45 :)
Answer:
The perimeter of a rectangle is the sum of both lengths and both widths, which is equal to 54 meters. Let's call Length L and Width W.
The question is saying this: L = 3 meters + 3(W). We have 2 variables, which means we need at least 2 equations to solve. So far we have one, our second equation is from the perimeter.
2 lengths + 2 Widths = 54. Now, it's just a plug and chug.
2(3 + 3W) + 2W = 54.
6 + 6W + 2W = 54
8W = 48
W=6
L = 3 + 3(6) = 21
To double check: 2(21) + 2(6) = 42 + 12 = 54
The Width is 6 meters, and the Length is 21 meters.
minimum value: 1
lower quartile: 3
median of the data: 6
upper quartile: 8
maximum value: 14
Sorry for the late answer, i hope this will help you in the future and everyone else who reads this.
Can you be more specific about what is P(5)? The probability would probably be around five though.
