Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
c
Step-by-step explanation:
symbols, sounds or pictures
hope this help
Answer: He had 14 more touchdowns than he did fumbles.
Step-by-step explanation:
Step 1. Ok, so we need to see how many times 9 will divide into 18.
18/9=2.
Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.
2*2=4
Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.
18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.
Hope this helps!
Answer is <span>x = -7
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