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3 years ago

Someone please help me with this question please!!!!!!

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

Answer: rewrite your equetion plz i cant understand it then i woill help u

Step-by-step explanation:

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How does the point of intersection of the graphs represent the solution of a system of linear equations

dybincka [34]

Answer:

The system of linear equations and the solution for the system is the value. It creates all of the equations true. 2 variables or 2 equations this is the point where the two graphs intersect.

Step-by-step explanation:

Its kina complicated...if you still don't understand don't worry i don't either:/

7 0

3 years ago

Please help! Will give brainliest

Nina [5.8K]

Answer:

d=1/2

b=1/25

b(row 2)=1/5

e=7/100

explanation: think about them as numbers out of 100 then simplify :)

7 0

3 years ago

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In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association a

RUDIKE [14]

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

5 0

2 years ago

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

Nezavi [6.7K]

Answer:

$x=c.a^{-1}.b^{-1}$

Step-by-step explanation:

Given equation,

$axb = c-----(1)$

$(axb) ( a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$

$(xb)(a)(a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$ ( commutative law of multiplication )

$(xb)(a.a^{-1}).b^{-1} = c.a^{-1}b{-1}$ ( Associative property )

$(xb).e.b^{-1} = c.a^{-1}b{-1}$

$(xb).b^{-1}=c.a^{-1}.b^{-1}$ ( identity property )

$x.(b.b^{-1})=c.a^{-1}.b^{-1}$ ( Associative property )

$x.e=c.a^{-1}.b^{-1}$

$x=c.a^{-1}.b^{-1}$ ( identity property )

5 0

3 years ago

This system has one solution.

mr_godi [17]

Answer: It is 2.

Step-by-step explanation:

Make both equation equal to each other and solve for x, as following:

- Add like terms.

- Factor the equation.

$8x-14=x^{2}+4x-10\\x^{2}+4x-10-8x+14=0\\x^2-4x+4=0\\(x-2)(x-2)=0\\(x-2)^2=0\\x=2$

Substitute the value of x obtained into any of the original equations to obtain the y-coordinate.

Then, this is:

$y=8(2)-14\\y=16-14\\y=2$

3 0

3 years ago

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