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Ne4ueva [31]
3 years ago
14

In 1999 there were 1647 daily and 7471 weekly newspapers published in the United States, as well as X other kinds of newspapers.

The total number of newspapers was 700 greater then seven times the number of other kinds of newspapers. How many newspapers were published in 1999 that were not daily or weekly
I NEED THIS ANSWER !!!! 90 POInTS
Mathematics
1 answer:
kompoz [17]3 years ago
4 0
I'll do the math for this, it may take me a few minutes so i will update this comment with an answer in just a minute. I always get anxious when nobody replies kind of quickly as i feel it is being forgotten. So just a heads up i'm working on a answer!
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If f(x)= 5x + 4 and g(x) = 1/2x<br><br> find ,<br> a) fg(5)
Veseljchak [2.6K]

Answer:

f(g(5)) = 16.5

Step-by-step explanation:

To calculate f(g(5)), evaluate g(5) then substitute the value obtained into f(x)

g(5) = \frac{1}{2} × 5 = 2.5 , then

f(2.5) = 5(2.5) + 4 = 12.5 + 4 = 16.5

5 0
3 years ago
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Help I be trying so but can figure out the answer
Sphinxa [80]

Answer:

b

Step-by-step explanation:

Surface of the earth =3959×3.14

=12,437.565

if 20%is suitable so we multiply it by the surface

12,437.565×0.2=2,487.513 per people

2,487.513/7,700,00,00

So I think it will be the closest to b

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3 years ago
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There are 7 colors on a color wheel . you have 25 spins to get blue. after 24 spins, you have not been successful . what is the
nadya68 [22]
B) 1/7 because no matter how many times you spin the odds are always 1 out of all 7 of the colors
7 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
Sarai is mixing a solution. She pours all the liquid from a full small beaker into a larger beaker. The liquid fills the large b
n200080 [17]

Answer:

2000 ml

Step-by-step explanation:

Given: Sarai pours all the liquid from a full small beaker into a larger    beaker.

           The liquid fills the large beaker to 15% of its capacity.

            The small beaker holds 300 ml.

Lets assume capacity of large beaker to hold be "x".

As given, Sarai pours all the liquid from a full small beaker into a larger beaker

∴ 15\% \times x= 300\ ml

⇒ 0.15x= 300

Dividing both side by 0.15

⇒x= \frac{300}{0.15}

∴ x= 2000\ ml

Hence, the large beaker can hold 2000 ml of liquid.

3 0
3 years ago
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