Answer:
force on the proton = 5.96 × 
N
Explanation:
given data
kinetic energy = 1.16 ×
eV
charge density of σ = +6.60 μC/m²
solution
we get here force on the proton that is express as
F = qE ....................1
here q is charge on proton i.e = 1.6 × 
C
and E is electric field due to charge i.e E = 
so put the value in equation 1 we get
force on the proton = 1.6 × × 
force on the proton = 5.96 × N
Explanation:
A) we know that the magnitude of force
= 4.761×10^{-4} N
Also, net force = gravitational force - electrostatic force
B) F_net = F_g - F_e
m×a = m×g - 4.761×10^-4
a = g - 4.761×10^{-4}÷m
a= 9.8 - (4.761×10^{-4}
/0.16×10^{-3})
a= 9.8 -2.975625
a= 6.82 m/s
Anions: negatively charged atoms
Cations: positively charged atoms (CAT-ions are PAWS-itively charged)
Anode: positively charged electrode that allows electrical current flow (positive end of battery)
Cathode: negatively charged electrode that allows electrical current flow (negative end of batter)
