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Agata [3.3K]
2 years ago
15

Objects 1 and 2 attract each other with a gravitational force of 179 units. If the distance separating objects 1 and 2 is change

d to four times the original value (i.e., quadrupled), then the new gravitational force will be ______ units.
Physics
1 answer:
yaroslaw [1]2 years ago
3 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between the 2 objects.

the distance is now quadrupled.

Fgravitynew = G*(mass1*mass2)/(4D)² =

= G*(mass1*mass2)/(16D²) =

= (G*(mass1*mass2)/D²) / 16 = Fgravity/16

the new gravitational force will be 179/16 = 11.1875 units

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Arte-miy333 [17]

Answer:

* Experiment with a higher range of materials

* Use a galvanometer.

* Vary in number of coils of the electromagnet

Explanation:

This is an experiment of electricity and magnetism, in general the best way to improve the results are:

* Experiment with a higher range of materials

   allowing to know the scope of the initial assumptions

* Use a galvanometer.

  The more accurate the readings the error of the derived quantities is the less which will improve the precision of the experiment.

* Vary in number of coils of the electromagnet

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3 0
3 years ago
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A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg
solong [7]

The  mass of the large truck is determined as 5680 kg.

<h3>Mass of the truck</h3>

The mass of the truck is calculated as follows;

P = mv

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m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

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7 0
1 year ago
Which statements correctly compare the gravitational force with the electrical force? Check all that apply.
skad [1K]

The statements that correctly compare the gravitational force with the electrical force are the following:

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3 years ago
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andreev551 [17]

Answer:

Rechargeable batteries can still go flat after repeated use because the materials involved in the reaction lose their ability to charge and regenerate

Explanation:

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7 0
2 years ago
A 60cm long string of an ordinary guitar is tuned to produce the note a4 (frequency 440hz) when vibrating in its fundamental mod
pishuonlain [190]

Answer:

0.78 m

Explanation:

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\lambda is the wavelength

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f=440 Hz is the frequency

v = 344 m/s is the speed of sound in air

Substituting into the equation and re-arranging it, we find the wavelength:

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