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stepan [7]
3 years ago
8

The temperature of an enclosure for a pet corn snake should be an average of 81° F. For the well-being of the corn snake, the te

mperature in the enclosure should not vary by more than 5° F. Which absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure?
Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer: |81-x|<5

Step-by-step explanation:

Given: Temperature of an enclosure for a pet corn snake should be an average of 81° F.

Temperature in the enclosure should not vary by more than 5° F.

Let x= Temperature in the enclosure

Then, difference between average and current temperature should less the 5.

i.e. |81-x|<5     (required absolute value equation  )

hence, the absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure:

|81-x|<5

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Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
2 years ago
2.7, #41 please. Thanks in advanced.
djverab [1.8K]

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3 years ago
If you were to use the substitution method to solve the following system, choose the new
mestny [16]

Answer:

23x = -115

Step-by-step explanation:

In the substitution method, you must solve for 1 variable in 1 equation to replace it in the other equation. For the system:

2x - 7y = 4

3x + y = -17

Solving for y in the second equation:

y = -17 - 3x

Replacing y in the first equation:

2x - 7(-17 - 3x) = 4

2x + 119 + 21x = 4

23x = -115

This is the new equation after use the substitution method.

5 0
3 years ago
A hot-air balloon at 1020 feet descends at a rate of 85 feet per minute. Let y represent the height of the balloon and let x rep
Lady_Fox [76]
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8 0
3 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
3 years ago
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