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stepan [7]
3 years ago
8

The temperature of an enclosure for a pet corn snake should be an average of 81° F. For the well-being of the corn snake, the te

mperature in the enclosure should not vary by more than 5° F. Which absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure?
Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer: |81-x|<5

Step-by-step explanation:

Given: Temperature of an enclosure for a pet corn snake should be an average of 81° F.

Temperature in the enclosure should not vary by more than 5° F.

Let x= Temperature in the enclosure

Then, difference between average and current temperature should less the 5.

i.e. |81-x|<5     (required absolute value equation  )

hence, the absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure:

|81-x|<5

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Pilar is playing with a motorized toy boat. She puts the boat in a lake and it travels 400m at a constant speed. On the way back
ankoles [38]

Answer:

The trip normally takes 8 minutes

Step-by-step explanation:

The given information states that the away distance the boat traveled = 400 m

The time traveled at the same initial  speed , v₁, by the boat on the way back = 2 minutes

The increase in speed of the boat by Pilar =  10 m/min

The new speed, v₂ = v₁ + 10

The time for the return trip, t₂ = 60 seconds (1 minute) faster than time for the trip, t₁

t₂ = t₁ - 1

Therefore we have;

v₁ × t₁ = v₁×2 + v₂×(t₂-2) = 400

v₁×2 + (v₁ + 10)×(t₂-2) = 400

(v₁ + 10)×t₂ - 20 = 400

But v₁ = 400/t₁ = 400/(t₂ + 1)

Which gives;

(400/(t₂ + 1) + 10)×t₂ - 20 = 400

10×(t₂²+ 36·t₂-2)/(t₂+1) = 400

10·t₂²+ 10·t₂-420 = 0

t₂²+ t₂-42 = 0

(t₂ - 7)(t₂ + 6) = 0

t₂ = 7 minutes or -6 minutes

Given that t₂ is a natural number, we have, t₂ = 7 minutes

Whereby, t₂ = t₁ - 1, we have;

7 =  t₁ - 1

t₁ = 1 + 7 = 8 Minutes

The trip normally takes 8 minutes

3 0
3 years ago
HELP PLEASE THANK YOU! :) 50 POINTS !!!!!!!1
a_sh-v [17]

Answer:  0.88

Step-by-step explanation:  

Let C is the event of drinking coffee, T is the event of drinking tea and M is the event of drinking milk.

Thus, when we make the Venn diagram of the given situation according to the given information,

Total number of people = 50

Number of people who like coffee, tea and milk = 19

Number of people who like coffee, tea but not milk = 16

Number of people who like coffee, milk but not tea = 2

Number of people who like tea, milk but not coffee = 5

Thus, the number of people who like tea only = Total people - (people who like coffee, tea but not milk + people who like coffee, tea and milk + the one who only like tea and milk but not coffee)

= 50 - ( 16 + 19 + 5) = 50 - 46 = 4

Thus, Total number of the person who like milk = 16 + 19 + 5 + 4 = 44

⇒ Probability that this person likes tea = \frac{\text{ Total person who like to drink milk}}{\text{ Total number of people}} = \frac{44}{50} = 0.88





3 0
3 years ago
It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe
lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u \frac{km}{hr}

Speed of current = v \frac{km}{hr}

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

32 = \frac{100}{u +v}

u + v = \frac{100}{32}

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

48 = \frac{100}{u -v}

u -v = \frac{100}{48}

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 \frac{km}{hr}

v = 0.5205 \frac{km}{hr}

Now the time taken by the un powered raft to cover this distance

T = \frac{100}{v}

Because un powered raft travel with the speed of the current.

T = \frac{100}{0.5205}

T = 192.12 hr

Therefore the  time taken by the un powered raft to cover this distance is

T = 192.12 hr

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3 years ago
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In mathematics it’s another term for isometry
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How many multiples of three are between 10 and 787 and show work pls
SOVA2 [1]
787-10=777
777/3=259

259 multiples of 3
8 0
3 years ago
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