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iris [78.8K]
4 years ago
12

You move down 3 units. You end at (5,-2). Where did you start?

Mathematics
1 answer:
timofeeve [1]4 years ago
3 0
I think it’s (5,-5)
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The product or three and a number n is less than or equal to 15.
koban [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
What is the height of an equilateral triangle with side lengths of 14?
olganol [36]
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC. 
5 0
4 years ago
Read 2 more answers
Determine whether AB and CÓ are parallel, perpendicular or neither.
IRISSAK [1]

Answer:

Neither

Step-by-step explanation:

They do not form a 90° angle(so it's not perpendicular)

And they touch(so it's not a parallel)

8 0
3 years ago
Use the rules for significant figures to find the answer to the addition problem 21.4 + 15 + 17.17 + 4.003
Whitepunk [10]

Given : The addition 21.4 + 15 + 17.17 + 4.003 by the rules for significant figures.

Solution: According to given numbers, let us count number of significant figures in each of the given numbers.

21.4 has three significant figures.

15 has two significant figures.

17.17 has four significant figures.

4.003 has four significant figures.

We have to round the final answer to the nearest tens place because 15 has only accurate to the ones place.

We can see that other numbers are accurate to the tenths, hundredths and thousandths places, respectively.

Let us add them as usually first,

21.4 + 15 + 17.17 + 4.003.

It gives 57.573.

Now, we need to round it to the ones place.

We get 58 as the final answer.

7 0
4 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
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