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Deffense [45]
3 years ago
10

What is the purpose of a system call in an operating system?

Computers and Technology
1 answer:
ikadub [295]3 years ago
6 0

Answer:

 The system call is the programming way for executing the requesting the services in the program from kernel in the particular operating system.

The main purpose of the system call in the operating system is that it basically provide the different types of the services to the users by using the API (Application program interface) system.

It basically provide the interface for allowing the users to request the services between the operating system and a processor. In the linux there are basically three types of system call are as follows:

  • Fork
  • Waitpid
  • Exist

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The birthday problem is as follows: given a group of n people in a room, what is the probability that two or more of them have t
Julli [10]

Answer:

import random

def calc_birthday_probability(num_people):

   num_tries = 1e6

   num_duplicates = 0

   tries = 0

   while tries < num_tries:

       total_birthday = {}

       for i in range(1, 366):

           total_birthday[i] = 0

       for count in range(num_people):

           birthday = random.randint(1, 365)

           if total_birthday[birthday] != 0:

               num_duplicates += 1

               break

           total_birthday[birthday] += 1

       tries += 1

   return num_duplicates/num_tries

def main():

   num_people = 10

   p = calc_birthday_probability (num_people)

   print(p)

   num_people = 20

   p = calc_birthday_probability (num_people)

   print(p)

   return

if __name__ == "__main__":

   random.seed(2020)

   main()

Explanation:

  • Run the loop until the value of tries is less than num_tries to do number of trials.
  • Run the loop to create the desired number of birthdays by generating random numbers.
  • Increase  the num_duplicates  variable by 1, if the birthday has  already occurred.
  • Lastly define and then call the main function.

4 0
4 years ago
As u type where does excel display the entry
grigory [225]

Answer:

The Active cell inside Excel Worksheet is used to identify the cell which is currently active. The thick border gridlines around the cell indicates that it is the Active cell inside Excel Worksheet. The Active cell is where the focus is on and where the data will be entered when a key is typed on keyboard.

5 0
3 years ago
What is the purpose of the Subtotal feature?
Svetradugi [14.3K]

Answer:

performs calculations

Explanation:

The SUBTOTAL function in Excel allows users to create groups and then perform various other Excel functions such as SUM, COUNT, AVERAGE, PRODUCT, MAX, etc. Thus, the SUBTOTAL function in Excel helps in analyzing the data provided.

5 0
2 years ago
What is the launching of a 3-D map called?
WARRIOR [948]

Answer:

A raised-relief map or terrain model is a three-dimensional representation, usually of terrain, materialized as a physical artifact.

Explanation:

<h2>P I E C K</h2><h2>_______</h2>
8 0
3 years ago
Write a program to sort an array of 100,000 random elements using quicksort as follows: Sort the arrays using pivot as the middl
Stels [109]

Answer:

Check the explanation

Explanation:

#include<iostream.h>

#include<algorithm.h>

#include<climits.h>

#include<bits/stdc++.h>

#include<cstring.h>

using namespace std;

int partition(int arr[], int l, int r, int k);

int kthSmallest(int arr[], int l, int r, int k);

void quickSort(int arr[], int l, int h)

{

if (l < h)

{

// Find size of current subarray

int n = h-l+1;

 

// Find median of arr[].

int med = kthSmallest(arr, l, h, n/2);

 

// Partition the array around median

int p = partition(arr, l, h, med);

 

// Recur for left and right of partition

quickSort(arr, l, p - 1);

quickSort(arr, p + 1, h);

}

int findMedian(int arr[], int n)

{

sort(arr, arr+n); // Sort the array

return arr[n/2]; // Return middle element

}

int kthSmallest(int arr[], int l, int r, int k)

{

// If k is smaller than number of elements in array

if (k > 0 && k <= r - l + 1)

{

int n = r-l+1; // Number of elements in arr[l..r]

 

// Divide arr[] in groups of size 5, calculate median

// of every group and store it in median[] array.

int i, median[(n+4)/5]; // There will be floor((n+4)/5) groups;

for (i=0; i<n/5; i++)

median[i] = findMedian(arr+l+i*5, 5);

if (i*5 < n) //For last group with less than 5 elements

{

median[i] = findMedian(arr+l+i*5, n%5);

i++;

}

int medOfMed = (i == 1)? median[i-1]:

kthSmallest(median, 0, i-1, i/2);

int pos = partition(arr, l, r, medOfMed);

if (pos-l == k-1)

return arr[pos];

if (pos-l > k-1) // If position is more, recur for left

return kthSmallest(arr, l, pos-1, k);

return kthSmallest(arr, pos+1, r, k-pos+l-1);

}

return INT_MAX;

}

void swap(int *a, int *b)

{

int temp = *a;

*a = *b;

*b = temp;

}

int partition(int arr[], int l, int r, int x)

{

// Search for x in arr[l..r] and move it to end

int i;

for (i=l; i<r; i++)

if (arr[i] == x)

break;

swap(&arr[i], &arr[r]);

 

// Standard partition algorithm

i = l;

for (int j = l; j <= r - 1; j++)

{

if (arr[j] <= x)

{

swap(&arr[i], &arr[j]);

i++;

}

}

swap(&arr[i], &arr[r]);

return i;

}

 

/* Function to print an array */

void printArray(int arr[], int size)

{

int i;

for (i=0; i < size; i++)

cout << arr[i] << " ";

cout << endl;

}

 

// Driver program to test above functions

int main()

{

float a;

clock_t time_req;

int arr[] = {1000, 10, 7, 8, 9, 30, 900, 1, 5, 6, 20};

int n = sizeof(arr)/sizeof(arr[0]);

quickSort(arr, 0, n-1);

cout << "Sorted array is\n";

printArray(arr, n);

time_req = clock();

for(int i=0; i<200000; i++)

{

a = log(i*i*i*i);

}

time_req = clock()- time_req;

cout << "Processor time taken for multiplication: "

<< (float)time_req/CLOCKS_PER_SEC << " seconds" << endl;

 

// Using pow function

time_req = clock();

for(int i=0; i<200000; i++)

{

a = log(pow(i, 4));

}

time_req = clock() - time_req;

cout << "Processor time taken in pow function: "

<< (float)time_req/CLOCKS_PER_S

return 0;

}

..................................................................................................................................................................................................................................................................................................................................

OR

.......................

#include <stdio.h>

#include <stdlib.h>

#include <time.h>

 

// Swap utility

void swap(long int* a, long int* b)

{

int tmp = *a;

*a = *b;

*b = tmp;

}

 

// Bubble sort

void bubbleSort(long int a[], long int n)

{

for (long int i = 0; i < n - 1; i++) {

for (long int j = 0; j < n - 1 - i; j++) {

if (a[j] > a[j + 1]) {

swap(&a[j], &a[j + 1]);

}

}

}

}

 

// Insertion sort

void insertionSort(long int arr[], long int n)

{

long int i, key, j;

for (i = 1; i < n; i++) {

key = arr[i];

j = i - 1;

 

// Move elements of arr[0..i-1], that are

// greater than key, to one position ahead

// of their current position

while (j >= 0 && arr[j] > key) {

arr[j + 1] = arr[j];

j = j - 1;

}

arr[j + 1] = key;

}

}

 

// Selection sort

void selectionSort(long int arr[], long int n)

{

long int i, j, midx;

 

for (i = 0; i < n - 1; i++) {

 

// Find the minimum element in unsorted array

midx = i;

 

for (j = i + 1; j < n; j++)

if (arr[j] < arr[min_idx])

midx = j;

 

// for plotting graph with integer values

printf("%li, %li, %li, %li\n",

n,

(long int)tim1[it],

(long int)tim2[it],

(long int)tim3[it]);

 

// increases the size of array by 10000

n += 10000;

}

 

return 0;

}

8 0
4 years ago
Read 2 more answers
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