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4 years ago

A flatbed truck is being loaded with steel girders weighing 1825 lbs each. How much will 15 of these girders weigh, combined?

1 answer:

6 0

I think I know how it's done!

You need to multiply 1825 by 15. You may want to show the work in this one.

1825•15 = 27,375

Thus, the truck will be loaded with 27,375 lbs of steel girders.

Hope this helps you succeed!

You might be interested in

In a stationary store,pencils have one price and pens have another price.Two pencils and three pens cost 78 cents.However, 3 pen

Tomtit [17]

Answer:

Pencils cost $0.12

Step-by-step explanation:

Set up a system of equations :D

let x represent pencils

let y represent pens

2x + 3y = 0.78

3x + 2y = 0.72

Because we are only interested in pencils we will solve for x first.

Isolate y in either equation, lets do the first one.

3y = 0.78 - 2x

y = (0.78 - 2x)/3

Simplify

y = 0.26 - (2x/3)

Now plug what we got into Y in the other equation

3x + 2 (0.26 - (2x/3)) = 0.72

solve by simplifying

3x + 0.52 - (4x/3) = 0.72

3x - (4x/3) = 0.20

9x/3 - 4x/3 = 0.20

lets change 0.2 into a fraction 2/10 simplified to 1/5

5x/3 = 1/5

25x/15 = 3/15

25x=3

x= 3/25 = 0.12

4 0

3 years ago

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f

tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :- f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x) to have a maximum or minimum at given point.

ii) find first derivative $f^{l} (x)$ and equating zero

iii) solve and find 'x' values

iv) Find second derivative $f^{ll}(x) >0$ then find the minimum value at x=a

v) Find second derivative $f^{ll}(x)$ then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

step1:- find first derivative $f^{l} (x)$ and equating zero

$f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)$

$f^{l}(x) = \frac{1}{x^2+1} (2x)$ ……………(1)

$f^{l}(x) = \frac{1}{x^2+1} (2x)=0$

the point is x=0

step2:-

Again differentiating with respective to 'x', we get

$f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}$

on simplification , we get

$f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}$

put x= 0 we get $f^{ll}(0) = \frac{2}{(1)^2}$ > 0

$f^{ll}(x) >0$ then find the minimum value at x=0

Final answer:-

The minimum value of the given function is f(0) = 0

5 0

4 years ago

roy is going to increase the size of his patio to make room for a new BBQ grill. The ratio oof the area of the old patio to the

luda_lava [24]

The issue here is to express fractions more easily:
2 1/4: 6 3/4
lets simplify fractions:
2 1/4 = 8/4 + 1/4 = 9/4
6 3/4 = 24/6 + 3/4 = 27/6
So the ratio can also be expressed as:
9/4 : 27/6
lets find a common denominator:
54/24 : 108/24
are also equivalent, so we can reduce:
54 : 108
and finally
1 : 2

4 0

4 years ago

Read 2 more answers

Hello if you can please explain.

Serhud [2]

Answer:

I think it should be A.

Step-by-step explanation:

8-1 is 7 which is very close to 6, and it says they are similar so this could work.

7 0

3 years ago

A store owner paid $20 for a book. She marked up the price of the book by 15% to determine its selling price. What is the sellin

TiliK225 [7]

Answer:

20 : 100% = x : 115%

Step-by-step explanation:

Do 115 x 20

divide the answer by 100

and that is your answer

8 0

3 years ago