What if I write the equation like this:
y = zero x - 3.
Now you know that the slope of the line is zero and its y-intercept is -3.
That's a horizontal line that crosses the y-axis at -3. And just like the equation says, the value of 'y' doesn't depend on 'x'. It's -3 everywhere.

Fiona and Pip win some money and share it in the ratio 6:1. Fiona gets £35 more than Pip. How much did they get altogether?


Let Pip get be x and fiona get be x+35
Ratio = 6:1





You could do 165,000 divided by 180,000. This is 165000/180000, and that will give you the percentage that 165000 is of 180000 in decimal form, which is 0.9167.
Then we round to the nearest tenth, which is 0.92
0.92 as a percentage is 92%.
100% - 92% = 8%
The price of the home dropped by 8%.
Answer: 0.42 mg
Step-by-step explanation:
Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.
Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = 

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg
Z, 0, X, 1, U, 2, Q, _, L, 4, F, ...
vodka [1.7K]
Answer:
3
Step-by-step explanation:
It's mostly an assumption based on the pattern of number placement, so I apologize in advance if this is incorrect.
I'm not sure what this is for.