Question

If a sample of pure silver (Ag) contains 3.35 x 1022 atoms of silver, how many moles of silver are in the sample?

Answer 1

Hey there!:

1 mole Ag ------------------- 6.02*10²³ atoms
moles Ag ?? --------------- 3.35 *10²² atoms

moles Ag = ( 3.35*10²² ) * 1 /  ( 6.02*10²³ ) = 

moles Ag = ( 3.35*10²² ) / ( 6.02*10²³ ) = 

=> 0.5564 moles of Ag

hope this helps!

Answer 2

Answer: The given number of silver atoms occupies 0.055 moles.

Explanation:

We are given:

Number of silver atoms = $3.35\times 10^{22}$

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

So, using this concept:

As, $6.022\times 10^[23}$ number of atoms occupies 1 mole of a element.

So, $3.35\times 10^{22}$ number of atoms will have occupy $\frac{1mole}{6.022\times 10^{23}}\times 3.35\times 10^{22}=0.055mole$ of silver element.

Thus, the given number of silver atoms occupies 0.055 moles.