Answer: The pH of the solution is 11.2
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
![Molarity=\frac{n\times 1000}{V_s}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7BV_s%7D)
where,
n = moles of solute
= volume of solution in ml
moles of
=
(1g=1000mg)
Now put all the given values in the formula of molality, we get
![Molarity=\frac{0.00507\times 1000}{170}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B0.00507%5Ctimes%201000%7D%7B170%7D)
![Molarity=0.0298](https://tex.z-dn.net/?f=Molarity%3D0.0298)
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![Ba(OH)_2\rightarrow Ba^{2+}+2OH^{-}](https://tex.z-dn.net/?f=Ba%28OH%29_2%5Crightarrow%20Ba%5E%7B2%2B%7D%2B2OH%5E%7B-%7D)
According to stoichiometry,
1 mole of
gives 2 mole of
Thus 0.0298 moles of
gives =
moles of
Putting in the values:
![pOH=-\log[0.0596]=2.82](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B0.0596%5D%3D2.82)
![pH+pOH=14](https://tex.z-dn.net/?f=pH%2BpOH%3D14)
![pH=14-2.82](https://tex.z-dn.net/?f=pH%3D14-2.82)
![pH=11.2](https://tex.z-dn.net/?f=pH%3D11.2)
Thus the pH of the solution is 11.2