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2 years ago

PLSSS HEALP ASAP!!!! WILL REWARD

Chemistry

1 answer:

Liula [17]2 years ago

6 0

A)1.75×3 moles of carbon monoxide

B)2:3

A)each mole of ferric oxide requires 3 moles of carbon monoxide. Therefore 1.75 moles requires 1.75 ×3 moles of carbon monoxide

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I need to know the measurements of this to the appropriate amount of significant figures

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Answer:

[See Below]

Explanation:

I'd say 44 something. It's probably ml but I can't see what it says on the tube.

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3 years ago

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Leto [7]

I would pick the first option in the third option

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3 years ago

A ______________________ is the distance from one compression to the next compression in a longitudinal wave.

svetoff [14.1K]

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2 years ago

If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did

user100 [1]

Answer:

4.5 L water we have in litres (L).

Explanation:

$Q=m\times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0 cal/(g℃))

m is the mass of water

Plugging in the values

$\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$$

So,

Volume of water = mass/density

$\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$$

=4.5 L (Answer)

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3 years ago

What material would be the best choice for the support beams of a building

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Steel would be the best choice for support beams

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3 years ago

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