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mixas84 [53]
3 years ago
6

What heat is liberated in the formation of 10.0 grams of sulfur hexafluoride, SF6, from the elements sulfur and fluorine?

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

Q=-76.7kJ

Explanation:

Hello,

In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:

n_{SF_6}=10.0gSF_6*\frac{1molSF_6}{146.06 gSF_6}=0.0685mol

Next, for the given energy, we compute the total heat that is liberated:

Q=-1220.47\frac{kJ}{mol}*0.0685 mol\\\\Q=-76.7kJ

Finally, we conclude such symbol has sense since negative heat is related with liberated heat.

Best regards.

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3 years ago
Breeder reactors are used to convert the nonfissionable nuclide U-238 to a fissionable product. Neutron capture by the U-238 is
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Pu-239

Explanation:

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3 years ago
What is the charge on an atom after it gains two electrons during the formation of a bond?
vekshin1

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8 0
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Each molecule of lycopene contains 40 atoms of carbon (plus other atoms). The mass percent of carbon in lycopene is 84.49%. What
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Answer: 568g/mol

Explanation:

It should be noted that there are 40 atoms of carbon in lycopene.

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Let the molar mass of lycopene be represented by x.

Therefore the molar mass of carbon = x × mass percent of carbon in lycopene

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The molar mass of lycopene is 568g/mol

5 0
3 years ago
HELP
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C, 0.746 mol Ag.

1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag

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