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tamaranim1 [39]
3 years ago
15

A line has two-fold

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

C. rotational

Step-by-step explanation:

Common figures with only rotational symmetry are the recycling sign and fan blades. If a figure coincides with the original twice in one full turn, it has two-fold rotational symmetry.

plz mark me as brainliest :)

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Here is a circle, centre 0, and the tangent to the circle at the
denpristay [2]

Answer:

y = \dfrac{7}{24}x + \dfrac{625}{24}

Step-by-step explanation:

The radius drawn to the tangent at the point of tangency is perpendicular to the tangent.

The radius has endpoints (0, 0) and (-7, 24). The slope of the line containing the radius is

m_r = \dfrac{24 - 0}{-7 - 0}

m_r = -\dfrac{24}{7}

The slope of the tangent is the negative reciprocal of the slope of the radius.

m_t = \dfrac{7}{24}

The tangent contains point (-7, 24).

y = mx + b

24 = \dfrac{7}{24}(-7) + b

24 = -\dfrac{49}{24} + b

\dfrac{576}{24} + \dfrac{49}{24} = b

b = \dfrac{625}{24}

The equation of the tangent is

y = \dfrac{7}{24}x + \dfrac{625}{24}

3 0
3 years ago
The points (2, 1.3), (3, 2.0), (4, 2.2), and (5, 2.8) are modeled by the function y = 0.5x + 0.4. Which graph correctly displays
butalik [34]
I think the answer is C. 
3 0
3 years ago
Need help with question​
Papessa [141]
The answer is the fourth choice
6 0
2 years ago
Maurissa has 1,965 stickers. She wants to divide them equally into 8 goodie bags. After separating the stickers, she realized sh
Nina [5.8K]

Answer:

5

Step-by-step explanation:

Maurissa has 1965 stickers, she wants to divide them equally into 8 bags

Therefore the amount of stickers that will be left after seperating them into the bags can be calculated as follows

= 1965/8

= 245 remainder 5

Hence the amount of stickers that will be left is 5

8 0
3 years ago
What is the following product? Assume d>/= 0
Hunter-Best [27]

Answer:

\boxed{\boxed{\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}=d}}

Step-by-step explanation:

The given expression is,

=\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}

It can also be written as,

=d^{\frac{1}{3}}\cdot d^{\frac{1}{3}}\cdot d^{\frac{1}{3}}

The exponent product rule of algebra states that, while multiplying two powers that have the same base, the exponents can be added.

As here all the terms have same base i.e d, so applying the rule

=d^{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}

=d^{\frac{1+1+1}{3}}

=d^{\frac{3}{3}}

=d^1

=d

5 0
3 years ago
Read 2 more answers
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