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Olin [163]
3 years ago
12

A cart is moving at 55 m/s at an angle of 25° to the ground. Determine the horizontal component.

Physics
1 answer:
Elodia [21]3 years ago
7 0

Answer:

<em>The horizontal component of the velocity is 49.85 m/s.</em>

Explanation:

<u>Rectangular Components of a Vector</u>

A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.

When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:

v_x=v\cos\theta

v_y=v\sin\theta

Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.

The cart is moving at v=55 m/s at θ=25°, thus:

v_x=55\cos 25^\circ

v_x=49.85\ m/s

The horizontal component of the velocity is 49.85 m/s.

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2x\frac{dx}{dt}=0+2e\frac{de}{dt}\\\\\frac{dx}{dt}=\frac{e}{x}\frac{de}{dt}

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x^2=23104+(91)^2\\\\x=\sqrt{31385}=177.16\ mi

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