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Ksivusya [100]
2 years ago
14

The larger the mass of a star, the higher the internal pressures. Higher internal pressures causes higher temperatures and it is

temperature that determines the types of fusion that can occur deep in a stars interior. Discuss the types of fusion that can occur in a star, the temperatures at which they occur, and the mass required to produce them.
Physics
1 answer:
hram777 [196]2 years ago
6 0

The types of fusion that occurs in stars are:

  • proton-proton fusion - stars with temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.
  • carbon cycle fusion - occurs in stars with temperatures of 15 million Kelvin or more and masses of 4.0 solar mass or more
  • helium fusion - occurs in stars with temperatures of 100 million Kelvin or more and masses of 0.5 solar mass or more

<h3>What is a nuclear fusion reaction?</h3>

A nuclear fusion is reaction in which nucleus of small atoms combine together to produces atoms of larger nucleus.

The types of nuclear fusion that can occur in a star include;

  1. Proton-proton fusion - occur in stars with core temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.
  2. Carbon cycle fusion occurs in stars with core temperatures greater than 15 million Kelvin having masses of 4.0 solar mass or more.
  3. Helium fusion - occurs in stars with core temperatures greater than 100 million Kelvin and masses of 0.5 solar mass or more

In conclusion, the types of fusion that occur in stars are proton-proton fusion, carbon cycle fusion and helium fusion.

Learn more about nuclear fusion at: brainly.com/question/982293

#SPJ1

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AYUDA :( Calcular el trabajo desarrollado por la fuerza de fricción, si la fuerza "F" desplaza al bloque de una distancia de 40m
kogti [31]

Answer:

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Explanation:

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4 0
3 years ago
A system consists of N particles that can occupy two energy levels: a nondegenerate ground state and a three-fold degenerate exc
cupoosta [38]

Answer:

Ng = 0.893 N,  Ne = 0.107N

Explanation:

Number of particles in Ground state = Ng

Number of particles in Excited state = Ne

Ne/Ng = e^{(-ΔE)/kt}

Since excited state is 3 fold degenerate

Ne/Ng =3 x e^{(-ΔE)/kt}

ΔE = Energy difference between ground and excited states = 0.25eV

T = 960 K

Constant k = 8.617 x 10^-5 eV/K

Ne/Ng = 3 x e^{-0.25/(8.617x10^-5) x 960}

           = 3 x e^(-3.188645)

           = 3 x 0.0412 = 0.1237 ≅ 0.12

Ne = 0.12 Ng

but Ne + Ng = N, where is N is total number of particles, substituting Ne into equation we get,

Ng(1 + 0.12) = N

Ng = N/1.12 = 0.893N

and Ne = 0.12 x 0.893 N = 0.107 N

3 0
3 years ago
How do most primary producers make their own food?​
MrRissso [65]

Answer:

in a kitchen

Explanation:

only if they're producing

3 0
3 years ago
Read 2 more answers
4. Describe how the velocity of an object changes if it undergoes uniformly acceleration motion. Can its direction change?
valentinak56 [21]

Answer:

n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

Explanation:

Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.

In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

              a_{t} = (v₂-v₁)/Δt

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

                    a_{c} = v2/R

In the general case, both the module and the address change

             a = Ra (  a_{t}^2 +   a_{c}^2)  

4 0
3 years ago
If a wave's third harmonic has a frequency of 24 Hz, what is its
Charra [1.4K]

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

f_n = nf_1

where

f_1 is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

f_3=24 Hz

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz

Now we can also find the frequency of the 6-th harmonic using n = 6:

f_6 = 6 f_1 = 6 (8)=48 Hz

6 0
3 years ago
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