Answer:
Ng = 0.893 N, Ne = 0.107N
Explanation:
Number of particles in Ground state = Ng
Number of particles in Excited state = Ne
Ne/Ng = e^{(-ΔE)/kt}
Since excited state is 3 fold degenerate
Ne/Ng =3 x e^{(-ΔE)/kt}
ΔE = Energy difference between ground and excited states = 0.25eV
T = 960 K
Constant k = 8.617 x 10^-5 eV/K
Ne/Ng = 3 x e^{-0.25/(8.617x10^-5) x 960}
= 3 x e^(-3.188645)
= 3 x 0.0412 = 0.1237 ≅ 0.12
Ne = 0.12 Ng
but Ne + Ng = N, where is N is total number of particles, substituting Ne into equation we get,
Ng(1 + 0.12) = N
Ng = N/1.12 = 0.893N
and Ne = 0.12 x 0.893 N = 0.107 N
Answer:
in a kitchen
Explanation:
only if they're producing
Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)
Answer:
8 Hz, 48 Hz
Explanation:
The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.
The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

where
is the fundamental frequency
In this problem, we know that the wave's third harmonic has a frequency of

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

Now we can also find the frequency of the 6-th harmonic using n = 6:
