To find the slope of the perpendicular line, you can take the negative reciprocal of the slope of the line it is perpendicular to.
Taking the negative reciprocal of -1/5 gives 5.
Now we have y=5x+b, where b is the y-intercept. Since we know that the perpendicular line passes through the point (1,4), we can substitute those values into the equation we have to find b.
y=5x+b
4=5(1)+b
4=5+b
b=-1
Therefore, the equation of the perpendicular line is y=5x-1.
If there are 8 groups of 65 students, that means they can seat 8*65 students total. 520 students
Domain={8,9}
Range = { -3,-4,-6,-9}
No relation is not function as elements in domain are related to more than one element of codomain
Answer:
A. y = -3/2x + 1
B. y = -5/3x + 10
C. y = -x + 6/5
Step-by-step explanation:
A. You just have to isolate the y so divide by 4: y = -3/2x + 1
B. 3y = -5x + 30
Divide by 3: y = -5/3x + 10
C. -5x + 6 = 5y
Divide by 5: -1x + 6/5 = y OR y = -x + 6/5
X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q = 10
answer is A.
