Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
Answer:
1) the third equation or X/2=2.0
2) 20 bucks
Step-by-step explanation:
for number 1 just plug in the x hi 4 and try to solve it
2) just calculate unit rate by 120/6=20
Answer:
The degrees of freedom are given by:
The p value for this case would be given by:
Step-by-step explanation:
Information given
represent the mean height for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
t would represent the statistic
represent the p value for the test
Hypothesis to verify
We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Replacing the info given we got:
The degrees of freedom are given by:
The p value for this case would be given by:
A= -5 is the correct answer
