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jolli1 [7]
3 years ago
14

The probability of getting a head when a biased coin is tossed is 2/5. The coin is tossed three times. Find the following probab

ilities and select the correct solution. P(three tails) = . P(two tails followed by one head) = .
Mathematics
1 answer:
NeTakaya3 years ago
6 0

Answer:

<u>P(three tails) = 27/125 or 21.6%</u>

<u>P(two tails followed by one head) = 18/125 or 14.4%.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the questions correctly:

Probability of getting a head when a biased coin is tossed = 2/5

therefore,

Probability of getting a tails when a biased coin is tossed = 3/5

2. Find the following probabilities and select the correct solution.

P(three tails) =

3/5 * 3/5 * 3/5 = 27/125 or 21.6%

P(two tails followed by one head) =

3/5 * 3/5 * 2/5 = 18/125 or 14.4%.

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Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

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\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

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P(x>1)= 1 - 0.368 - 0.442=0.190

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P(Y>1)=1- P(Y=0)

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