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2 years ago

Julian is 10 years younger than Thomas. The sum of their age is 40. What is Thomas age

1 answer:

3 0

So first we subtract 10 from 40 and get 30. We divide this by the number of people (2) to get Julian's age: 15. We add 10 to this to get Thomas age = 25. 25 + 15 = 40

Thomas is 25 years old.

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Help pls?? will give brainilest <3

N76 [4]

Answer:

The y = 0.5 the x = 1

Step-by-step explanation:

The y = 0.5 the x = 1

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2 years ago

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Meredith was paid $18 for recycling 30 pounds glass. What is this rate payment

hammer [34]

$1.67 for each pound of glass

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2 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

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1 year ago

Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x)

Snowcat [4.5K]

Answer:

A. f(x) = x^2 + 4x + 3

D. f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

The axis of symmetry is found by h = -b/2a where ax^2 +bx +c

A. f(x) = x^2 + 4x + 3

h = -4/2*1 = -2 x=-2

B. f(x) = x^2 - 4x - 5

h = - -4/2*1 = 4/2 =2 x=2 not -2

C. f(x) = x^2 + 6x + 2

h = -6/2*1 = -3/2 = x=-3/2 not -2

D. f(x) = -2x^2 - 8x + 1

h = - -8/2*-2 = 8/-4 =-2 x=-2

E. f(x) = -2x^2 + 8x - 2

h = - 8/2*-2 = -8/-4 =2 x=2 not -2

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2 years ago

True or false: a pair of straight angles can also be adjacent angles

IrinaK [193]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions. the statement "a pair of straight angles can also be adjacent angles" is true

There are some special relationships between "pairs" of angles. Adjacent Angles are two angles that share a common vertex, a common side, and no common interior points. (They share a vertex and side, but do not overlap.) A Linear Pair is two adjacent angleswhose non-common sides form opposite rays.

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2 years ago

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